The function will simply get reflected about the y-axis.
Let's approach this through what we know. Since we know that the x values are mirrored, we know that the points in Quadrant I and IV will be reflected over to the negative side, Quadrants II and III, because they simply change in signs.
However, we also know that the function y-values do not change. This is because whatever the x values are don't change the range and y-values of an even function.
To be more specific, if we have an even function, we are most likely dealing with quadratics or variants/transformations of the quadratic function.
If we were to have 2, and -2, and we wanted to plug them into the equation:

, the signs do not change the y-values of the function.
Hence, we know that it ONLY gets reflected across the y-axis.
Answer:
Yes it has
Step-by-step explanation:
From my perspective.........
f(x) = -4(x + 3)² - 5
f(x) = -4(x + 3)(x + 3) - 5
f(x) = -4(x² + 6x + 9) - 5
f(x) = -4x² - 24x - 36 - 5
f(x) = -4x² - 24x - 41
Dy/dx = -8x - 24
At minimum Dy/dx = 0
-8x - 24 = 0
-8x = 24
x = 24/-8
x = -3
At minimum
y = -4x² - 24x - 41
y = -4(-3)² - 24(-3) - 41
y = -4(9) + 72 - 41
y = -36 + 72 - 41
y = 36 - 41
y = -5
Answer:
u can
Step-by-step explanation:
u most square root both sides