Answer:
Refer picture enclosed
Step-by-step explanation:
Given is a line BA and a point P. We have to construct a line perpendicular to BA through P.
Case I: P lies on the line BA
Without loss of generality assume BP is smaller than AP.
Cut an arc C on AB from P such that BP=CP
Now with B and C as centres draw arc up and down the line with more than half length of BC
Join the intersecting of arcs. That line is the perpendicular for BA through P.
This is because of concurrency of two triangles above the line BC
Case2:
P lies outside the line. Measure PB and cut an arc of BA with length PB
Let the point be C
Then CP=BP
NOw do as we did before the line with arcs more than 1/2 length of BC from B and C only down. Join the point of intersection down with P. This line will be perpendicular through P to BA
Answer:28
Step-by-step explanation:
Answer:
The equation r = 3 - cos Ф is correct for the graph ⇒ 3rd answer
Step-by-step explanation:
Equations of the form r = a + b sin Ф, r = a - b sin Ф, r = a + b cos Ф, and r = a - b cos Ф represent limacons
- Equations r = a + b sin Ф, r = a - b sin Ф are symmetric to the vertical axis
- Equations r = a + b cos Ф, r = a - b cos Ф are symmetric to the horizontal axis
- The shape of the limacons depends on the values of a and b
∵ The figure is a circle
- That means a is greater than twice b
∴ a > 2b
∵ The circle is symmetric to the x axis
∵ The majority of the circle lies in quadrants two and three
- That means most of the graph at the negative part of x
∴ The form of the equation is r = a - b cos Ф
Lets look to the answer to find the right one
∵ a > 2b
∴ a = 3 and b = 1 because 3 > 2(1)
∴ The answer is r = 3 - cos Ф
The equation r = 3 - cos Ф is correct for the graph
1,000,000
2,500,000x0.4 (40 as a decimal) = 1,000,000
Let d represent the distance of the destination from the starting point.
After 45 min, Henry has already driven d-68 miles. After 71 min., he has already driven d-51.5 miles.
So we have 2 points on a straight line:
(45,d-68) and (71,d-51.5). Let's find the slope of the line thru these 2 points:
d-51.5 - (d-68) 16.5 miles
slope of line = m = ----------------------- = ------------------
71 - 45 26 min
Thus, the slope, m, is m = 0.635 miles/min
The distance to his destination would be d - (0.635 miles/min)(79 min), or
d - 50.135 miles. We don't know how far his destination is from his starting point, so represent that by "d."
After 45 minutes: Henry has d - 68 miles to go;
After 71 minutes, he has d - 51.5 miles to go; and
After 79 minutes, he has d - x miles to go. We need to find x.
Actually, much of this is unnecessary. Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is
(0.635 miles/min)(8 min) = 5.08 miles. Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.