Answer:
x = 8
y = -7
Step-by-step explanation:
This is a system of equations called simultaneous equations. We shall solve it by elimination method Step 1We shall label the equations (1) and (2)−3y−4x=−11.....(1)3y−5x=−61......(2)Step 2Multiply each term in equation (1) by 1 to give equation (3)1(-3y-4x=-11).....(1)-3y-4x=-11....(3)Step 3Multiply each term in equation 2 by -1 to give equation (4)-1(3y−5x=−61)......(2)-3y+5x=61.....(4)Step 4-3y-4x=-11....(3)-3y+5x=61.....(4)Subtract each term in equation (3) from each term in equation (4)-3y-(-3y)+5x-(-4x)=61-(-11)-3y+3y+5x+4x=61+110+9x=729x=72Step 5Divide both sides of the equation by 9, the coefficient of the unknown variable x to find the value of x 9x/9 = 72/9x = 8Step 6Put in x = 8 into equation (2)3y−5x=−61......(2)3y-5(8)=-613y-40=-61Collect like terms by adding 40 to both sides of the equation 3y-40+40=-61+403y=-21Divide both sides by 3, the coefficient of y to find the value of y 3y/3=-21/3y=-7Therefore, the values of x and y that satisfy the equations are 8 and -7 respectively
Answer:
angle Z=20°
side xy≈15.36
hypotenuse≈19.49
Step-by-step explanation:
Find angle z adding the other two angles and subtracting that by 180 to get 20.
(12)tan(20) gets you side xy which is 15.36
12^2+15.36^2=xz^2
Given options : Two intersecting circles are drawn with a radius in each marked. the image will be linked.
Given options : An equilateral triangle inscribed in a circle
A square inscribed in a circle
A regular pentagon inscribed in a circle
A regular hexagon inscribed in a circle.
<u>Note. When we join an intersection point of two circles and centers of the circles it would form an equilateral triangle that would be inscribe inside a common portion of both circles..</u>
Therefore, an equilateral triangle inscribed in a circle would be correct option.
She is completing an equilateral triangle inscribed in a circle.
Hello!
Since D is the midpoint and the two equations are and both sides of point D the equations equal each other
9x - 7 = 3x + 17
Now you solve it algebraically
Add 7 to both sides
9x = 3x + 24
Subtract 3x from both sides
6x = 24
Divide both sides by 6
x = 4
Now we put this into both equations and add them
9(4) - 7 = 29
3(4) + 17 = 29
29 + 29 = 58
The answer is 58 units
Hope this helps!
