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SOVA2 [1]
2 years ago
15

Prove the identity 2csc2x=csc^2xtanz

Mathematics
1 answer:
Verizon [17]2 years ago
7 0

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

2 \csc(2x)  =  \csc {}^{2} (x)  \tan(x)

2 \frac{1}{ \sin(2x) }  =  \csc {}^{2} (x)  \tan(x)

2  \times \frac{1}{2 \sin(x)  \cos(x) }  =  \csc {}^{2} (x)  \tan(x)

\frac{1}{ \sin(x) \cos(x)  }  =   \csc {}^{2} (x)  \tan(x)

\csc(x)  \sec(x)  =  \csc {}^{2} (x)  \tan(x)

Consider the RHS

\csc(x)  \sec(x)  =( 1 +  \cot {}^{2} (x) ( \tan(x))

\csc(x)  \sec(x)  =  \tan(x)  +  \cot(x)

\csc(x)  \sec(x)  =  \frac{ \sin(x) }{ \cos(x) }  +  \frac{ \cos(x) }{ \sin(x) }

\csc(x)  \sec(x)  =  \frac{1}{ \sin(x) \cos(x)  }

\csc(x)  \sec(x)  =  \csc(x)  \sec(x)

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Step-by-step explanation:

<u>Step 1:</u>

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