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Lynna [10]
3 years ago
8

Of 201 adults selected randomly from one town, 179 have credit cards. Find a 90% confidence interval for the true proportion of

all adults in the town who have credit cards.​
Mathematics
1 answer:
tino4ka555 [31]3 years ago
7 0

Answer:

I think this is a probability problem.

Step-by-step explanation:

201*0.9 the divide by 179??

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1,-2,3,-4,5... <br><br> what’s the next two numbers in the pattern?
MrMuchimi

Answer:

The two numbers following 1,-2,3,-4,5...  are -6 and 7.

Step-by-step explanation:

index:   1   2   3   4   5 ....

value:    1  -2  3  -4   5

Let the index be n.  Then the first term is a(1), the secon is a(2), and so on.

a(2) = 2*(-1)^(2-1) = 2*(-1) = -2 (correct)

a(3) = 3*(-1)^(3-1)   =  3*(-1)^2 = 3 (correct)

a(4) = 4*(-1)^(4-1)    = 4*(-1)^3 = -4 (correct)

So the general formula for a(n)  is:    a(n)=n(-1)^(n-1)

Thus,

a(5) = 5(-1)^4 = 5

a(6) = 6(-1)^5 = -6

a(7) = 7(-1)^6 = 7

The "next two numbers in the pattern" are -6 and 7.  The first 7 numbers are

1,-2,3,-4,5, -6, 7

4 0
3 years ago
I need help on this homework
abruzzese [7]

Answer:

Tn=a(n-1)d

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5 0
3 years ago
4.4 + [4 • 1/4 + 8.6]
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Answer: 4.4 + (4 x 1/4 + 8.6) = 14

Step-by-step explanation: Because starting inside the parenthesis, 4 times 1/4 = 1. Then 8.6 plus 1 = 9.6. Finally, 9.6 plus 4.4 which equals 14. :)

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Answer:

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Step-by-step explanation:

Just had it on a test and got it write

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