The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Answer:
(√6 - √2)/4
Step-by-step explanation:
cos30°cos45° - sin30°sin45°
= cos (30 + 45)°
= cos 75°
= (√6 - √2)/4
Answer:
100 ft²
Step-by-step explanation:
There are 4 congruent sides in a square
Perimeter = 4x
40 = 4x
x = 10
Area = base x height or length x width
Since all sides are the same, 10 is base and height
10x10 = 100
units = ft²
Answer = 100 ft²
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K