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tino4ka555 [31]
3 years ago
15

Ethan earns $10 every hour for walking Ms. Barn's two dogs, plus an additional $7

Mathematics
1 answer:
MatroZZZ [7]3 years ago
3 0
H=hour
10h+7=32 would be the best equation. Hope this helps!
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Explain 15 is not a prime factor
MissTica

<em>1</em><em>5</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>a</em><em> </em><em>prime</em><em> </em><em>factor</em><em> </em><em>as</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>1</em><em>,</em><em>3</em><em>,</em><em>5</em><em> </em><em>and</em><em> </em><em>1</em><em>5</em><em>.</em>

<em>Additional</em><em> </em><em>information</em><em>:</em>

<em>Prime</em><em> </em><em>numbers</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>only</em><em> </em><em>be</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>itself</em><em> </em><em>.</em><em>for</em><em> </em><em>instance</em><em>:</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em><em> </em><em>,</em><em>1</em><em>1</em><em>,</em><em>1</em><em>3</em><em> </em><em>etc</em><em>.</em>

<em>Composite</em><em> </em><em>number</em><em> </em><em>s</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>also</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>other</em><em> </em><em>numbers</em><em>,</em><em>For</em><em> </em><em>instance</em><em>:</em><em> </em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>1</em><em>0</em><em> </em><em>etc</em>

<em>Hope</em><em> </em><em>it </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

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05.06)Which of the following best describes interval C on the graph shown?
Korolek [52]
Linear decreasing

I haven't learned this is class yet, but I had a bf that taught me this
8 0
3 years ago
Read 2 more answers
124 ounces decreased by 67%
slavikrds [6]
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3 years ago
On a class trip to the museum,5/8 of the students saw the dinosaurs and 7/8 of the students saw either the jewelry collection or
inessss [21]

\frac{2}{8} of students only saw jewelry collection

<em><u>Solution:</u></em>

Given that, On a class trip to the museum,5/8 of the students saw the dinosaurs

7/8 of the students saw either the jewelry collection or the dinosaurs

<em><u>To find: Fraction of students only saw jewelry collection</u></em>

From given statement,

Fraction of students saw dinosaur = \frac{5}{8}

Fraction of students saw either the jewelry collection or the dinosaurs = \frac{7}{8}

Therefore,

Fraction of students only saw jewelry collection = Fraction of students saw either the jewelry collection or the dinosaurs - Fraction of students saw dinosaur

\rightarrow \frac{7}{8} - \frac{5}{8} = \frac{7-5}{8} = \frac{2}{8}

Thus \frac{2}{8} of students only saw jewelry collection

8 0
3 years ago
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