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sergeinik [125]
3 years ago
11

Product of a 3-digit number and a 1-digit number

Mathematics
2 answers:
nirvana33 [79]3 years ago
5 0
The product if a 3 digit number and a 1 digit number is 325 x 6 = 1950
zlopas [31]3 years ago
4 0

Answer: 100 * 2=200

Step-by-step explanation:

100 is a three digit number and 2 is a one digit number and if you multiply or find the product it is 200.

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Why is this simplified by combining like terms <br> 3(4x+5) +2
Inga [223]
3(4x+5)+2
3•4x=12x
5•3=15+2=17
Answer= 12x + 17
3 0
3 years ago
Suppose f(x) =x^2 and g (x) = 2x -3 what is the value of g (4)+f(-3)
Alona [7]

Answer:

d

Step-by-step explanation:

u just have to plug in the numbers

f(-3)= -3^2

f(-3)= 9

g(4)=2(4)-3

g(4)=5

9+5=14

I hope I'm right and hope I helped:)

6 0
3 years ago
a wrestler is weighing in for their match this evening. their normal weight is 168 pounds, but that weight can vary by as much a
Natalija [7]

<em>Introduction </em>

<em>Wrestling is a wonderful activity with many advantages for the student-athlete. It is a sport that is highly </em>

<em>competitive, exciting and satisfying. It is a sport that provides for individual and team competition. It is - </em>

<em>and should be - fun. Unfortunately, the practice of losing weight by not eating, restricting fluid intake and </em>

<em>over-exercising reduces the sport's fun. This information is presented to help clear up misconceptions </em>

<em>regarding wrestling and weight loss. I also hope to give some guidance to those who desire to manage </em>

<em>their weight properly in preparation for and during the wrestling season. </em>

<em>History and Stigma </em>

<em>For too long, the wrestling community has unthinkingly accepted the myth that to be a good wrestler, you </em>

<em>must cut weight. The generally accepted thinking is something like this: if your natural weight is 135 </em>

<em>pounds, you may be a good wrestler at 135 pounds. But if you wrestle at 130 pounds, you'll be a better </em>

<em>wrestler. And if you can make it down to 125, you'll be a state champion. No facts support that widely held </em>

<em>view, yet wrestlers and parents subscribe to that faulty reasoning. Looking further back, many remember </em>

<em>the days that losing excessive weight was a specific practice and expectation among wrestlers. It was </em>

<em>supposed to teach sacrifice, commitment, and the idea of “No Pain, No Gain.” </em>

<em>Regardless of the current attitude of the majority of the wrestling community, the stigma that an unhealthy </em>

<em>loss of weight is a requirement of wrestling among outside observers sticks. The Virginia High School </em>

<em>League has followed national guidelines to establish rules that encourage healthy weight management </em>

<em>among wrestlers. </em>

<em>Current Regulations </em>

<em>Preseason weight certification is accomplished with three steps. The first is determining each wrestler’s </em>

<em>body fat percentage using skin fold calipers. Next, the wrestler completes a hydration test, to insure </em>

<em>against a dehydrated weight measurement, and the wrestler weighs in. The third step is the calculation of </em>

<em>the wrestler’s minimum wrestling weight based on 7% body fat for males and 12% for females. The </em>

<em>wrestler may not wrestle at a weight class below his minimum weight during the season. The wrestler is </em>

<em>also restricted from losing more then 1.5% body weight loss per week (official weigh-ins at certification, </em>

<em>matches, and tournaments are used for this calculation). A one-pound per month growth allowance is </em>

<em>provided to allow for the natural growth of this age group. The VHSL advises, and we have instituted, </em>

<em>daily weigh-ins before and after practice to monitor weight-loss and dehydration. </em>

<em>Additionally, the National Federation of State High School Associations has adopted several other rules to </em>

<em>guide coaches and wrestlers while managing their weight. Wrestlers are discouraged from wrestling at a </em>

<em>weight class more then one weight class above their certified weight. </em>

5 0
3 years ago
A rectangular prism with a volume of 2 cubic units is filled with cubes with side lengths of 1/4 unit. How many 1/4 unit cubes d
alekssr [168]

Answer:

<em>128</em>

Step-by-step explanation:

<em>Method A.</em>

The volume of the prism is 2 cubic units.

Each cube has side length of 1/4 unit.

The volume of each cube is (1/4)^3 cubic unit.

The volume of each cube is 1/64 cubic unit.

To find the number of cubes that fit in the prism, we divide the volume of the prism by the volume of one cube.

(2 cubic units)/(1/64 cubic units) =

= 2/(1/64)

= 2 * 64

= 128

<em>Method B.</em>

Imagine that the prism has side lengths 1 unit, 1 unit, and 2 units (which does result in a 2 cubic unit volume.) Since each cube has side length 1/4 unit, then you can fit 4 cubes by 4 cubes by 8 cubes in the prism. Then the number of cubes is: 4 * 4 * 8 = 128

4 0
3 years ago
Read 2 more answers
Solve this proportion pls<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%20%2B%203%7D%7B4%7D" id="TexFormula1" title="\fr
emmasim [6.3K]

\bf \cfrac{x+3}{4}=\cfrac{7}{8}\implies 8(x+3)=4(7)\implies 8x+24=28\implies 8x=4 \\\\\\ x=\cfrac{4}{8}\implies x=\cfrac{1}{2}

8 0
3 years ago
Read 2 more answers
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