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sergeinik [125]
3 years ago
11

Product of a 3-digit number and a 1-digit number

Mathematics
2 answers:
nirvana33 [79]3 years ago
5 0
The product if a 3 digit number and a 1 digit number is 325 x 6 = 1950
zlopas [31]3 years ago
4 0

Answer: 100 * 2=200

Step-by-step explanation:

100 is a three digit number and 2 is a one digit number and if you multiply or find the product it is 200.

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One of the roots of the quadratic equation x^2−5mx+6m^2=0 is 36. Find the greatest possible value of the second root. 100PTS!!!
rosijanka [135]

Answer:

The greatest possible value is 54

Step-by-step explanation:

Solve the quadratic equation

Given

x² - 5mx + 6m² = 0

We can rewrite this as

x² - 3mx - 2mx + 6m² = 0

(x² - 3mx) - (2mx - 6m²) = 0

x(x - 3m) - 2m(x - 3m) = 0

(x - 2m)(x - 3m) = 0

x - 2m = 0 or x - 3m = 0

So,

x = 2m or x = 3m .

2m and 3m are the roots of the equation.

Since one of the roots is 36

Assume

2m = 36

m = 36/2 = 18

3m is

3(18) = 54

If 3m = 36

m = 12

And

2m = 2(12) = 24.

The greatest possible value is 54

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