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4 years ago

Product of a 3-digit number and a 1-digit number

Mathematics

2 answers:

nirvana33 [79]4 years ago

5 0

The product if a 3 digit number and a 1 digit number is 325 x 6 = 1950

zlopas [31]4 years ago

4 0

Answer: 100 * 2=200

Step-by-step explanation:

100 is a three digit number and 2 is a one digit number and if you multiply or find the product it is 200.

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PLEASE HELP!! 20 POINTS

natali 33 [55]

Answer:

5/12

Step-by-step explanation:

take the number of students who read under6 books (5) and divide by total amount of students (12)

5/12

5 0

3 years ago

Read 2 more answers

What is directly in between 0.5 and 1.0?

ki77a [65]

.75 because .75 is .25 from 1.0 and .25 from .5

7 0

3 years ago

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Help me out please?<br>chapter : exponents and powers

belka [17]

Answer:

$\frac{125}{27}$

Step-by-step explanation:

$\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}$

Lets expand all the composite numbers into prime numbers.

$=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}$

Lets cancel $2^{-4}$ from numerator and denominator.

$=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}$

Using laws of exponents , lets solve this.

$=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}$

$=> \frac{3^{-3} \times 5^{1}}{5^{-2}}$

$=> 3^{-3} \times 5^{[1 - (-2)]}$

$=> 3^{-3} \times 5^{3}$

$=> \frac{5^3}{3^3} = \frac{125}{27}$

4 0

3 years ago

Read 2 more answers

A geometric sequence is shown below: a0, -11, 22, a1, 88, -176.

Anon25 [30]

The common ratio looks like -2 (-11 * -2 =22) and the missing terms are -44 and 352. (22*-2=-44, -176*-2=352).

8 0

3 years ago

What is x to the power of 3 divided by x to the power of -5

Veseljchak [2.6K]

X to the power of 8
When dividing powers, you subtract the "small numbers". When multiplying, you add them. 3-(-5) = 8

Hope it helps!

4 0

3 years ago