Please help me!

I have a coil of steel that is 48 inches wide. The weight of the coil is 10.800 kegs. If I cut the coil a width of 0.5 inches ho

MakcuM [25]

0.1125 kg

Step-by-step explanation:

Step 1:

Let us assume that 48 inches of coil of steel weighs 10.800 kg.

We have to find the weight of 0.5 inch coil.

Step 2:

In this problem we assume that it is given in direct relationship.

Therefore, Problem becomes

48 inches weigh 10.8 kg

0.5 inches weigh X kg

(48 / 0.5) = ( 10.8 / X)

X = (10.8 × 0.5) / 48

X = 0.1125 kg

3 0

3 years ago

A circular region has a population of about 15,500 people and a population density of about 775 people per square kilometer. Fin

Reil [10]

Answer:

2.5 km

Step-by-step explanation:

First, find the area of the region:

A circular region has a population of about 15,500 people;
A population density of about 775 people per square kilometer.

So, there are $15,500 :775=20$ square kilometers.

Now, let x kilometers be the radius of the circular region, then

$A_{\text{circilar region}}=\pi r^2\\ \\20=\pi r^2\\ \\r^2=\dfrac{20}{\pi}\approx 6.366198\\ \\r=\sqrt{3.366198}\approx 2.523$

To the nearest tenth this is 2.5 km.

6 0

3 years ago

Which of these taxes helps provide health insurance for people who are retired or disabled?

Mkey [24]

FICA tax, otherwise known as social security

4 0

3 years ago

In a recent year, students taking a mathematics assessment test had a mean of 290 and a standard deviation of 37. Possible test

cricket20 [7]

Answer:

a) 79.10% probability that a student had a score less than 320.

b) 46.63% probability that a student had a score between 250 and 300.

c) 99.25% of the students had a test score greater than 200

d) 350.865

e) 265.025

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 290, \sigma = 37$