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marin [14]
3 years ago
8

Determine the number of real solutions of the equation. Then solve the equation using square roots

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

x ∉ R

Step-by-step explanation:

x² = - 21

if x² < 0 => x ∉ R

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Please i need your help in this question, i will mark you to brainliest ​
ICE Princess25 [194]

Answer:

\frac{2520}{64}  {ln}^{3}

Step-by-step explanation:

V=L×W×H

=3½in×1⅞×2¾

=3×2+1/2in × 1×8+7/8in × 2×4+3/4in

=7/2in × 15/8in × 24/4in

=2520/64 incube

so it's you tern to change into mixed fraction

sorry for that

but if it's helpful ❤❤

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8 0
2 years ago
Which exponential function has an initial value of 2?<br><br> f(x) = 2(3x)<br><br> f(x) = 3(2x)
Sidana [21]
<span>f(x) = 2(3x)
Exponential functions represent the initial value outside of the parentheses so if 2 is the initial value it has to be on the outside of the parentheses. 
Exponential growth formula.
</span>y=a(1+r)^{x}
<span>a represents the initial value.</span>
7 0
3 years ago
Read 2 more answers
A new soda machine has 50 options to customize any type of drink you would like at a movie theater. Customers can choose any 4 o
Delicious77 [7]

Answer:

i like sprite

Step-by-step explanation:

3 0
3 years ago
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
The quadrilateral WXYZ has vertices W(3,-5) X(1,-3) Y(-1,-5) and Z(1,-7)
dmitriy555 [2]
The preimage WXYZ is to undergo a rotation of 90° in the clockwise direction.
A 90° clockwise rotation leads to the following change in the coordinates;
(x,y) -> after rotation (y,-x)
this rule applies for all the vertices in the preimage
W - (3,-5)  --> W' (-5,-3)
X - (1,-3) ---> X' (-3,-1)
Y - (-1,-5)---> Y' (-5,1)
Z - (1,-7) ---> Z' (-7,-1)
therefore the new coordinates are W' (-5,-3), X' (-3,-1), Y' (-5,1) and Z' (-7,-1)
5 0
2 years ago
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