Solve the inequality , find the max possible value for the variable.
3t + 1 < t + 12
2t < 11
t < 5.5
t_max = 5.5
For the second question just solve as two separate inequalities
4 +2 < x <= 7 + 2
6 <x <= 9
x in ]6, 9]
Answer:
Nope they are the exact same
2*2*4+2*2*24+2*4*24
16+96+192=304
304 is the answer
Answer:
0.736
Step-by-step explanation:
Divide 92/125
7____ is the one that couldn't used to complete a table of eqiuvalent ratios
