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bogdanovich [222]
3 years ago
14

Show the formula for finding the area of a triangle. Then find the area of a right triangle with a base of 19 cm and a height of

6.5 cm.
Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0
The answer is 61.75 because you have to do base times height then divide that answer by two
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Two mechanics worked on a car. The first mechanic worked for 15
nevsk [136]

Answer: For the sum of 130

First: $90

Second: $40

Step-by-step explanation:

We write equations for each part of this situation.

<u>The Total Charge</u>

Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.

<u>The Sum of the Rates</u>

Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.

We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.

For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.

15a + 5 (130-a)=1550

15a+650-5a=1550

10a+650-650=1550-650

10a=900

a=$90 was charged by the first mechanic.

We substitute to find the second mechanic's rate.

90+b=130

90-90+b=130-90

b= $40 was charged by the second mechanic

5 0
3 years ago
Can u help ill make u brainliest
Paul [167]

Answer:

x = 21/5 (4 1/5

Solve:

x + 4/5 - 4/5 = 5 - 4/5

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4 0
2 years ago
Read 2 more answers
50 PTS! NEED HELP NOW!
nordsb [41]

Answer:

maybe its just me but I cant see it :( blurry

Step-by-step explanation:

4 0
3 years ago
Pls just ans the match the following bless yal stay safe
Vilka [71]

Answer:

a-ii

b-iii

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e-vi

please mark as brainliest

4 0
3 years ago
The median of a continuous random variable having distribution function F is that value m such that F(m) = 1/2 . That is, a rand
neonofarm [45]

Answer:

Step-by-step explanation:

To find median and mode for

a) In a uniform distribution median would be

(a+b)/2 and mode = any value

b) X is N

we know that in a normal bell shaped curve, mean = median = mode

Hence mode = median = \mu

c) Exponential with parameter lambda

Median = \frac{ln2}{\lambda }

Mode =0

7 0
3 years ago
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