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My name is Ann [436]
3 years ago
5

Find the missing symbol: 1/6 ? 1/2<>=please help​

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

1/6 < 1/2

Step-by-step explanation:

The larger the denominator, the smaller that fraction would be. Both of the numerators are equal, so we don't have to worry about that. Since 6 is larger than 2, we know that 1/2 is larger than 1/6. hope I helped:))

Anna [14]3 years ago
6 0
The missing symbol is <
1/6 is less than 1/2. Draw a diagram to help
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He radius of a circle is 2 kilometers. What is the area of a sector bounded by a 45° arc?
faust18 [17]
We know that
area of a circle=pi*r²
for r=2 km
area of a circle=pi*2²-----> 12.56 km²

if 360° (full circle) has an area of---------> 12.56 km²
 45°---------------------------------> x
x=45*12.56/360-----> x=1.57 km²

the answer is
1.57 km²
7 0
3 years ago
1,10,100,1000 common difference
alina1380 [7]
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3 years ago
The balloon has a radius of 6 what is the volume of the balloon
KIM [24]
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6 0
4 years ago
Is -5 greater than -9
sveta [45]

Answer: Yes! -5 is greater than -9, because with negatives the smaller numbers are the greatest because they are below 0. Have a good day and Good Luck!


Step-by-step explanation:


4 0
4 years ago
Read 2 more answers
M is the midpoint of CD. Given the coordinates of one endpoint C(10,-5) and the midpoint M(4, 0), find the coordinates of the ot
mash [69]

Answer:

D(-2, 5).

Step-by-step explanation:

We are given that M is the midpoint of CD and that C = (10, -5) and M = (4, 0).

And we want to determine the coordinates of D.

Recall that the midpoint is given by:

\displaystyle M = \left(\frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2}\right)

Let C(10, -5) be (<em>x</em>₁<em>, y</em>₁) and Point D be (<em>x</em>₂<em>, y</em>₂). The midpoint M is (4, 0). Hence:

\displaystyle (4, 0) = \left(\frac{10+x_2}{2} , \frac{-5+y_2}{2}\right)

This yields two equations:

\displaystyle \frac{x_2 + 10}{2} = 4\text{ and } \frac{y_2 - 5}{2} = 0

Solve for each:

\displaystyle \begin{aligned}x_2 + 10 &= 8 \\ x_2 &= -2 \end{aligned}

And:

\displaystyle \begin{aligned} y_2 -5 &= 0 \\ y_2 &= 5\end{aligned}

In conclusion, Point<em> </em>D = (-2, 5).

5 0
3 years ago
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