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Whitepunk [10]
3 years ago
15

$27.99 shoes ; 7 1/2 tax find the total cost or sale price to the nearest cent

Mathematics
2 answers:
yan [13]3 years ago
6 0

Answer:

$The total cost or sale price  = $30.09

Step-by-step explanation:

The total cost or sale price is the absolute price of a commodity including the given tax.

From the question given, the tax is 7\frac{1}{2}% of the price. So that;

Tax = 7\frac{1}{2}% × 27.99

      = 0.075 × 27.99

      = 2.09925

∴ Tax  = $2.09925

The total cost or sale price = price + tax

                                             = $27.99 + $2.09925

                                            = $30.08925

The total cost or sale price  = $30.09

Vinvika [58]3 years ago
5 0
27.99x.075= 2.09925 or 2.10 Rounded
27.99+2.10= $30.09

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The basketball team will need 196 fluid ounces of Gatorade for their tournament. How many cups will this equal?
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Step-by-step explanation:

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Solve for x<br><br> 2x - 1 - 1 = x - 3 - ( -5 + x )
Nana76 [90]

Answer:

x=2

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

2x−1−1=x−3−(−5+x)

2x−1−1=x−3+−1(−5+x)(Distribute the Negative Sign)

2x−1−1=x+−3+(−1)(−5)+−1x

2x−1−1=x+−3+5+−x

2x+−1+−1=x+−3+5+−x

(2x)+(−1+−1)=(x+−x)+(−3+5)(Combine Like Terms)

2x+−2=2

2x−2=2

Step 2: Add 2 to both sides.

2x−2+2=2+2

2x=4

Step 3: Divide both sides by 2.

2x

2

=

4

2

x=2

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3 years ago
Which of the following will increase the gravitational force exerted by one object on another? No links plz
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Step-by-step explanation:

3 0
3 years ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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