I need answers please just a few is fine

Mathematics

1 answer:

alina1380 [7]3 years ago

4 0

The second one is correct so its 2

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The first side of a triangle is 7cm less than twice the second side. The third side is 4cm longer than the first side. The perim

Vinil7 [7]

Given:

First side(A): 2B - 7

Second side(B): B

Third side(C): B + 4

Plug in values:

A + B + C = 80

2B - 7 + B + B + 4 = 80

If you look at the coefficients only, you can rewrite the equation like this:

2B + B + B - 7 + 4 = 80

This means that 4B - 7 + 4 = 80

=4B - 3 = 80

= 4B = 80 + 3

B = 83/4, so you can either write B as 83/4 or as 20.75.

Checking your work:

A: 2(20.75) - 7 = 34.5

B: 20.75

C: 4 + 20.75 = 24.75

34.5 + 20.75 + 24.75 = 80cm.

Hope this helped.

3 0

3 years ago

Find all solutions of each equation on the interval 0 ≤ x < 2π.

Korvikt [17]

Answer:

$x = 0$ or $x = \pi$ .

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

$\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}$ .

$\displaystyle \sec{x} = \frac{1}{\cos{x}}$ .

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, $\sin^{2}{x} = 1 - \cos^{2}{x}$ . Therefore, for the square of tangents,

$\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}$ .

This equation will thus become:

$\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2$ .

To simplify the calculations, replace all $\cos^{2}{x}$ with another variable. For example, let $u = \cos^{2}{x}$ . Keep in mind that $0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1$ .