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3 years ago

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Round the following numbers to 2 decimal places

1 answer:

alexira [117]3 years ago

6 0

Before I give you the answers, there is a simple rule to observe when rounding a number to two decimal places. If the number in the third decimal place is less than five, then the number in the second decimal place stays the same. If the number in the third decimal place is five or greater than five, the number in the second decimal place is incremented by one. In our case the above numbers are rounded up as follows:

0.273 is rounded up to 0.27
1.595 is rounded up to 1.60
6.473 is rounded up to 6.47
2.571 is rounded up to 2.57
0.425 is rounded up to 0.43
44.5564 is rounded up to 44.56
82.3643 is rounded up to 82.36
325.1741 is rounded up to 325.17

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4 years ago

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igor_vitrenko [27]

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3 years ago

What is the product of -6/11 *3/4 in lowest terms? A. -9/22 B. -6/13 C. 9/22 D. 6/13

Dima020 [189]

<span>-6/11 *3/4 = -9/22

I hope this help !</span>

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3 years ago

Need help! Will mark Brainiest!

kicyunya [14]

Option B: $y=-\sqrt[3]{x-4}+7$ is the new equation

Explanation:

The given equation is $y=-\sqrt[3]{x}$

We need to find the new graph which is shifted 7 units up and 4 units right.

First, we shall shift the graph 7 units up.

The general formula to shift the graph b units up is given by

$y=f(x)+b$

Thus, to shift the graph 7 units up, let us substitute $b=7$ and $f(x)=-\sqrt[3]{x}$ in the general formula, we have,

$y=$-\sqrt[3]{x}$+7$

Now, we shall shift the graph 4 units right.

The general formula to shift the graph b units right is given by

$y=f(x-b)$

Thus, to shift the graph 4 units right, let us substitute $b=4$ and $f(x)=$-\sqrt[3]{x}+7$$ in the above equation, we have,

$y=-\sqrt[3]{x-4}+7$

Therefore, the new equation is $y=-\sqrt[3]{x-4}+7$

Therefore, Option B is the correct answer.

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3 years ago

Suppose you deposit $1,000 in a savings account that pays interest at an annual rate of 4%. If no money is added or withdrawn fr

raketka [301]

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Step-by-step explanation:

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3 years ago