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Juli2301 [7.4K]
2 years ago
7

Tia's tent is in the form of a triangular prism as shown below.

Mathematics
1 answer:
Ludmilka [50]2 years ago
7 0

Answer: 279.43

Step-by-step explanation:

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What property is -37=5b+13 is written as 5n+13=-37
PtichkaEL [24]

Answer:

reflexive

Step-by-step explanation:


5 0
4 years ago
Simplify 6+2X8-12+9 divided by 3
Elis [28]

6 + 2*8 - 12 + 9

= 6 + 16 - 12 + 9

= 19

19/3 = 6 1/3 answer

8 0
3 years ago
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I need help on all of these please help i’ll mark brainliest!!! <br> -11 + x = 7X - 5
nalin [4]

I don't know what your looking for, so be more specific, but I'm assuming your solving for x, so that's would be

x = -1

8 0
3 years ago
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13 gallons of water are used to completely fill 3 fish tanks. If each tank holds the same amount of water, how many gallons will
Pepsi [2]

Answer:

4 1/3

Step-by-step explanation:

12/3=4

1/3+4=4 1/3

7 0
3 years ago
Use the quadratic formula to solve each equation.
Elden [556K]

Answer:

1) x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2) x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3) p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4) y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

Step-by-step explanation:

The quadratic formula is given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}

x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}

x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}

p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}

y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

8 0
4 years ago
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