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Anit [1.1K]
3 years ago
9

A square pyramid has a base with side lengths each measuring 40 inches. The pyramid is 21 inches tall, with a slant height of 29

inches. What is the surface area of the pyramid? The base of a cylinder has a radius of 9 centimeters.
Mathematics
2 answers:
melomori [17]3 years ago
8 0

Answer:

3280 square inches

Step-by-step explanation:

The surface area of square pyramid = 4* the area of the triangular side + the area of the square base.

TRIANGULAR SIDE

The pyramid has an isosceles triangular side of size, a=40 inches, b= 29 inches, c = 29 inches.

Surface area = sqrt{ s(s-a)(s-b)(s-c) }

Where s= (a+b+c)/2

S= (40+29+29)/2 = 49

Surface area = sqrt{ 49(49-40)(49-29)(49-29)}

Surface area = 420 square inches

SQUARE BASE

Area of a square = a²

Area = 40² = 1600 square inches

Surface area of the pyramid = 4*420 + 1600 = 1680 + 1600

Surface area = 3280 square inches.

Daniel [21]3 years ago
5 0

Answer:

3,920

Step-by-step explanation:

Just took the test

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Answer:

2 23/27

Step-by-step explanation:

3 2/3 / 1 2/7

= 11/3 / 1 2/7

= 11/3 / 9/7

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Hope it helped!

6 0
3 years ago
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Answer with Step-by-step explanation:

The given differential equation is

(2x+5y)dx+(5x-4y)dy=0

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Checking for exactness we should have

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}

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The solution of exact differential equation is given by

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The value of \phi (y) can be obtained by differentiating u(x,y) partially with respect to 'y' and equating the result with P(x,y)

\frac{\partial u}{\partial y}=\frac{\partial (x^2+5xy+\phi (y)))}{\partial y}=Q(x,y))\\\\5y+\phi '(y)=(5x-4y)\\\\\phi '(y)=5x-9y\\\\\int\phi '(y)\partial y=\int (5x-9y)\partial y\\\\\phi (y)=5xy-\frac{9y^2}{2}\\\\\therefore u(x,y)=x^2+10xy-\frac{9y^2}{2}+c

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Answer:

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Step-by-step explanation:

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Step 3: Divide both sides by -2.

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3 0
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