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kvasek [131]
2 years ago
6

Do the equations 5y-2x=18 and 6x=-4y-10 form a system of linear equations?

Mathematics
1 answer:
Aneli [31]2 years ago
8 0
Yes, because 5y-2x=18 and 6x=-4y-10 are both linear equations in the same variables, they form a system of linear equations.
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Ichika is the best quintuplet
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2 years ago
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Place 3 numbers between 12 and 60 to make a sequence of 5 numbers with a common difference
Vilka [71]

The 3 numbers which should be placed between 12 and 60 are; 24, 36 and 48.

<h3>What three numbers should be placed between 12 and 60?</h3>

It follows from the task content that the first and last numbers are; 12 and 60 respectively.

Hence, since the difference between 12 and 60 is 48 and there are 4 transitions between the two numbers to have 5 total numbers,

It follows that the common difference is; 48/4 = 12 and the three numbers required are; 24,36 and 48.

Read more on common difference;

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5 0
2 years ago
The average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. Some of the weights of the fish are shown i
UNO [17]

Answer:

14.6

Step-by-step explanation:

It is given that,

The average weight of the top 5 fish caught at a fishing tournament was 12.3 pounds. From the attached figure, the weight of 5 fish are given. We need to find the weight of Wayne S. fish.

Average = sum of terms/no of terms

Let the weight of Wayne S. is x. So,

Here the sum of terms is x+12.8+12.6+11.8+9.7 and the number of terms is 5.

12.3=\dfrac{x+12.8+12.6+11.8+9.7}{5}\\\\61.5=x+12.8+12.6+11.8+9.7\\\\61.5=x+46.9\\\\x=14.6

So, the weight of the heaviest fish is 14.6.

3 0
3 years ago
Can I pls have help w/ this? How many 1/8 pound servings of walnuts, s , are in 3/4 pound of walnuts? ____ servings.
pychu [463]

Answer:

Okay the answer is 6/8

Step-by-step explanation:

1/4 is equal to 2/8 so take 3/4 and simplify to 8s which is 6/8.

8 0
3 years ago
The fuel efficiency for a 2007 passenger car was 31.2 mi/gal. For the same model of car, the fuel efficiency increased to 35.6 m
Ierofanga [76]

We have been given that fuel efficiency for a 2007 passenger car was 31.2 mi/gal and the same model of car, the fuel efficiency increased to 35.6 mi/gal in 2012. Also, the gas tank for this car holds 16 gallons of gas.

We need to write a function and graph a linear function that models the distance that each car can travel for a given amount of gas up to one tankful.

Let represent the functions as d_{1}(x) and d_{2}(x)  where d_{1} and d_{2} represent the distances traveled by car in years 2007 and 2012 and x represents the number of gallons. Therefore, we can express the required functions as:

d_{1}(x)=31.2x \text{ and } d_{2}(x) = 35.6x

Domain of both these functions are [0,16] and ranges are [0,499.2] and [0,569.6] respectively for years 2007 and 2012.

The difference function will be:

f(x)=35.6x-31.2x\\&#10;f(x)=4.2x

f(16)=4.2*16=67.2

Domain of this function is [0,16] and range is [0,67.2].

The graphs are shown below.


3 0
3 years ago
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