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FinnZ [79.3K]
3 years ago
9

Jennifer is saving money to buy a bike. The bike costs $246. She has $138 saved, and each week she adds $18 to her savings.

Mathematics
1 answer:
Brrunno [24]3 years ago
6 0

Answer: 8 weeks

explanation: 125 + 15x = 245

You then have to subtract 125 from both sides so we can isolate our variable which will give us 15x = 120 . Divide 15 from both sides : 15x/15 = 120/15 which will give us x = 8.

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The total cost in dollars to buy uniforms for the players on a volleyball team can be found using the function c=34.95u + 6.25,
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Answer:

is the 8 or the 12 supposed to be the u?

Step-by-step explanation:

6 0
3 years ago
How do you do this ?
Ivenika [448]

Good morning ☕️

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Answer:

4

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Step-by-step explanation:

Just solve the equation 5-√x = 3

So, let’s solve it:

5-√x = 3 ⇔ 5-3=√x ⇔ √x = 2 ⇔ x=4

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3 0
3 years ago
9(y-4) -3y = 2(3y-2 need solved as fast as possible
Vlad [161]

Step-by-step explanation:

did you give us all the information ? the equating looks cut off.

so, from what I can see we have

9(y-4) - 3y = 2(3y-2)

let's try :

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7 0
3 years ago
The science club advisor expects that between 42 and 49 students will attend Science Club field trip. The school allows $5.50 pe
baherus [9]

Answer:

$269.50

Step-by-step explanation:

Between 42-49

So, you have to assume 49 students will arrive, better to have more and have left overs than get less and not find kids.

As for math you just do 49 x 5.50 = 269.5

Finally that measn the budget for the food is $269.50

8 0
3 years ago
Prove the theorem which states that the angle subtended by a cord is twice at the centre than at the circumference
Novay_Z [31]

9514 1404 393

Explanation:

<u>Given</u>:

  • The attached figure showing circle O, chord BC, central angle BOC and inscribed angle BAC
  • angle BAC = α + β

<u>Prove</u>:

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<u>Proof</u>:

∠BOA +∠BOC +∠AOC = 360° . . . . . sum of arcs of a circle is 360°

2α +∠BOA = 180°, 2β +∠AOC = 180° . . . . . sum of triangle angles is 180°

∠BOA = 180° -2α, ∠AOC = 180° -2β . . . . solve statement 2 for central angles

(180° -2α) +∠BOC +(180° -2β) = 360° . . . . . substitute into statement 1

∠BOC = 2(α +β) . . . . . add 2α+2β-360° to both sides

∠BOC = 2×∠BAC . . . . . substitute given for α+β; the desired conclusion

7 0
3 years ago
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