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3 years ago

What construction does the image below demonstrate?

Mathematics

2 answers:

Nadya [2.5K]3 years ago

6 0

That should be B.An equilateral triangle inscribed in a circle

yanalaym [24]3 years ago

5 0

An equilateral triangle inscribed in a circle

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I have 1 word problem and a math problem. (word prob)A light-year is the distance that light travels in a year and is equivalent

Sati [7]

Answer:

1. 9461000000000

move the desimal in 9.461 12 places to the right to get:

9461000000000

5.85 x 10^-3,

2.5 x 10^-1,

3.6 x 10^8,

8.5 x 10^8,

8.5 x 10^12

the smallest exponent is the smallest. Since 8.5 x 10^8 and 3.6 x 10^8 have the same exponent, go to the desimal

6 0

3 years ago

Please help!!!!! Will give brainliest!!

valkas [14]

2.57*10^4 is 1,000,000 times more than 2.57*10^-1

Why?

4-(-1)=5 2

2.57*10^4=25700

2.57*10^-1=0.0257

and

25700

÷ 0.0257

=1000000

and 1000000=10^6

6 0

3 years ago

Represent each fraction on the number line 0————1

Akimi4 [234]

The answers are 1/5,2/5,3/5,and 4/5

5 0

4 years ago

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

castortr0y [4]

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

$F=ma$

Part a) Solve this equation for a

$F=ma$

Divide both sides by the mass

$a=\frac{F}{m}$

therefore

the answer part a) is equal to

$a=\frac{F}{m}$

Part b) Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

$a=\frac{F}{m}$

in this problem

we have

$F=25\\m=10$

Substitute the values n the formula

$a=\frac{25}{10}$

$a=2.5$

therefore

the answer part b( is equal to

$a=2.5$

Part c) Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

$F=ma$

Solve for m

Divide both sides by the acceleration

$m=\frac{F}{a}$

in this problem

we have

$F=25\\a=5$

Substitute the values n the formula

$m=\frac{25}{5}$

$m=5$

therefore

the answer Part c) is

$m=5$

5 0

3 years ago

Read 2 more answers

The height of a punted football can be modeled by the function: f(x) = -.0079 x2 + 1.8x + 1.5. In this equation, f(x) is the hei

mars1129 [50]

Answer:

Step-by-step explanation:

The function used to represent the height of a punted football can be modeled as

f(x) = -.0079x² + 1.8x + 1.5

Where f(x) is the height in feet, and x is the horizontal distance, also in feet.

a) when the ball was punted, x = 0, therefore, the height of the punted ball would be

f(x) = -.0079(0)² + 1.8(0) + 1.5

f(x) = 1.5 feet

The height is 1.5 feet

b) The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height reached by the punted ball.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = - 0.0079

b = 1.8

Vertex = - - 1.8/0.0079 = 227.84 feet

So the maximum height of the punt is 227.84 feet

3 0

3 years ago