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2 years ago

8

Write an equation of the line that passes through (18,2) and is parallel to the line 3y-x=-12 .

1 answer:

Xelga [282]2 years ago

5 0

Answer:

$y = \frac{1}{3}x-4$

Step-by-step explanation:

<u>Step 1: Solve for y in the first equation</u>

$3y - x = -12$

$3y - x + x = -12 + x$

$\frac{3y}{3} = \frac{x}{3} - \frac{12}{3}$

$y = \frac{1}{3}x - 4$

<u>Step 2: Determine the important aspects</u>

We know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3. We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equation

Point Slope Form → $(y-y_1) = m(x - x_1)$

<u>Step 3: Plug in the information and solve</u>

$(y-2) = \frac{1}{3}(x - 18)$

$y - 2 = \frac{1}{3}x - 6$

$y - 2 + 2 = \frac{1}{3}x - 6 + 2$

$y = \frac{1}{3}x-4$

Answer: $y = \frac{1}{3}x-4$

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Please answer me this question

Jobisdone [24]

Answer:

x = 2

y = 3

Step-by-step explanation:

$\left \{ {{0.4x + 0.3y = 1.7} \atop {0.7x - 0.2y = 0.8}} \right.$

$\left \{ {{2(0.4x + 0.3y) = 2 * 1.7} \atop {3(0.7x - 0.2y) = 3 * 0.8}} \right.$

$\left \{ {{0.8x + 0.6y = 3.4} \atop {2.1x - 0.6y) = 2.4}} \right.$

$2.9x = 5.8$

$29x = 58$

$x = 2$

$0.3y + 0.4x = 1.7$

$0.3y + 0.4 * 2 = 1.7$

$0.3y + 0.8 = 1.7$

$0.3y = 0.9$

$3y = 9$

$y = 3$

4 0

3 years ago

Find the missing side lengths

diamong [38]

Answer:

90

Step-by-step explanation: A right triangle will always add up to 180 seeing that the other two add up to 90 the last side is 90

3 0

3 years ago

Read 2 more answers

The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti

DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

$P(t)=10000(0.2)^t$

1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

$\frac{P(1)}{P(0)}$

$\frac{10000(0.2)^1}{10000(0.2)^0}$

$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

$P(t)=10000(0.2)^{t}$

We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) $P(12)=10000(0.87449)^{12}=2000 \text{approximately}$

b) $P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}$

c) $P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}$

d) $P(12)=10000(0.87449)^{12+12}=400 \text{approximately}$

So a is the function we want.

Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

$P(t)=10000(.2^\frac{1}{12})^t$ where $t$ is in months.

And $.2^\frac{1}{12}=0.874485 \text{approximately}$

8 0

4 years ago

DiKsa [7]

2.50 that is the answer

8 0

3 years ago

.At Phil’s work, there are 12 part-time workers and 18 full-time workers. What is the ratio of part-time workers to total worker

Scrat [10]

Answer:

2/5

Step-by-step explanation:

The desired ratio is ...

(part-time)/(total) = (part-time)/((part-time) +(full-time)) = 12/(12+18)

= 12/30 = 2/5

The ratio of part-time workers to total workers is 2 : 5.

7 0

3 years ago