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Bond [772]
2 years ago
8

Write an equation of the line that passes through (18,2) and is parallel to the line 3y-x=-12 .

Mathematics
1 answer:
Xelga [282]2 years ago
5 0

Answer:

y = \frac{1}{3}x-4

Step-by-step explanation:

<u>Step 1:  Solve for y in the first equation</u>

3y - x = -12

3y - x + x = -12 + x

\frac{3y}{3} = \frac{x}{3} - \frac{12}{3}

y = \frac{1}{3}x - 4

<u>Step 2:  Determine the important aspects</u>

We know that our line is parallel to the other line that has a slope of 1/3 which means that our slope is also going to be 1/3.  We also know that our line crosses the point (18, 2) which means that we can use the point slope form to determine our equation

Point Slope Form → (y-y_1) = m(x - x_1)

<u>Step 3:  Plug in the information and solve</u>

(y-2) = \frac{1}{3}(x - 18)

y - 2 = \frac{1}{3}x - 6

y - 2 + 2 = \frac{1}{3}x - 6 + 2

y = \frac{1}{3}x-4

Answer: y = \frac{1}{3}x-4

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