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TEA [102]
3 years ago
9

F(x) = -(x-3) +x What is f(-1) = ?

Mathematics
1 answer:
Lana71 [14]3 years ago
8 0

Explanation:

Let y=3x

To calculate the inverse, interchange

x and y,    

x =3 y

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The length of time of the school field day was decreased
Tju [1.3M]
18% because take the first digits of each number and put them together lol
8 0
3 years ago
Solve x - 5y = 6 for x.<br> Ox= -5y + 6<br> Ox= -5y - 6<br> Ox = 5y + 6<br> Ox = 5y - 6
valentina_108 [34]

Answer:

See below

Step-by-step explanation:

Solve x-5y=6 for x

First, we need to isolate the x by moving -5y to the other side.

To do this, we need to add 5y to both sides

x - 5y=  6

  +5y   +5y

x= 5y+6

So, your third answer is correct

8 0
3 years ago
357,335 rounded to the nearest ten357,335 rounded to the nearest ten
Advocard [28]

Answer:

357,340

Step-by-step explanation:

Locate the tens place:

357,3<u>3</u>5

Check the number to the right:

357,33<u>5 </u>

<u></u>

If the number is greater than or equal to 5, then we round up. If the number is less than or equal to 4, we round down.

The number next to the tens place is a '5'. We round up.

357,335 ≈ 357,340

Hope this helps.

5 0
3 years ago
There are two precalculus sections at a high school. Mr.​ Abel's class has 14 girls and 8 ​boys, while Mr.​ Bonitz's class has 1
Gemiola [76]

Answer:

14/46

Step-by-step explanation:

4 0
3 years ago
1. Homer has an idea for a new donut shop. He wants to design the donut shop so that the rectangular
Tju [1.3M]

Solving a <em>system of equations</em>, it is found that since the <u>quadratic equation has two positive roots</u>, they can be the values of the length and the width, and the design is possible.

The perimeter of a <u>rectangle of length l and width w</u> is given by:

P = 2(l + w)

The area is:

A = lw

In this problem, perimeter of 63.5 m, hence:

2l + 2w = 63.5

2l = 63.5 - 2w

l = 31.75 - w

Area of 225 m², hence:

lw = 225

(31.75 - w)(w) = 225

w^2 - 31.75w + 225 = 0

Which is a quadratic equation with coefficients a = 1, b = -31.75, c = 225.

Then:

\Delta = b^2 - 4ac = (-31.75)^2 - 4(1)(225) = 108.0625

w_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{31.75 + \sqrt{108.0625}}{2} = 21.1

w_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{31.75 - \sqrt{108.0625}}{2} = 10.68

Since the <u>quadratic equation has two positive roots</u>, they can be the values of the length and the width, and the design is possible.

A similar problem is given at brainly.com/question/10489198

6 0
2 years ago
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