Does the graph above have an Hamiltonian circuit, Hamiltonian path, or neither? Paths and Circuits Help

Mathematics

1 answer:

Hatshy [7]2 years ago

6 0

a. Only a Hamiltonian path

One such path is

1 → 2 → 0 → 4 → 3

which satisfies the requirement that each vertex is visited exactly once.

There is no Hamiltonian circuit, however, since it is impossible for any Hamiltonian path on this graph to visit vertex 0 exactly once.

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