Answer:
120 ways
Step-by-step explanation:
Given that, 3-letter sequences should be formed, where the second letter must be a vowel (A, E, I, O, U) and the third letter must differ from the first letter.
There are 26 alphabets in English,
so, firstly let us fix the second letter to be one of the vowels
now we are left with 25 alphabets and now let us fix the third letter to be an alphabet from the remaining 25 alphabets.
now, we are left with 24 alphabets and the first letter can be any of these 24 alphabets.
so, there are 24 ways to fill the sequence.
The same thing can be done with the other 4 vowels.
so, total number of ways = 5 × 24 = 120 ways.
