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3 years ago

Whats the range of y=2x-7

2 answers:

6 0

Answer:

(-∞,∞) or {y|y∈R}

Step-by-step explanation:

Digiron [165]3 years ago

6 0

Y= -5x that’s what I think

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MakcuM [25]

x=20(y−3)2−1

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3 years ago

3241004551 [841]

Step-by-step explanation:

Blue is for physics........

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2 years ago

maxonik [38]

$\dfrac 1{ab} + \dfrac{a^2}{b^2}\\\\\\=\dfrac{b+a^3}{ab^2}\\\\\\=\dfrac{a^3 +b}{ab^2}$

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2 years ago

Anni [7]

I think the answer is r=8..
hope this helps!:)

6 0

3 years ago

vazorg [7]

If $x+a$ is a factor of the polynomial, it means that $-a$ is a root of the polynomial.

In fact, if a polynomial $p(x)$ has a root $x_0$ (i.e. $p(x_0)=0$ ), then the polynomial is divisible by $(x-x_0)$

In your case, you know that the polynomial is divisible by $(x+a)=(x-(-a))$ , so $-a$ is a solution.

Let's evaluate $p(-a)$ and set it to zero:

$2(-a)^2+2a(-a)+5(-a)+10 = 0 \iff 2a^2-2a^2-5a+10=0 \iff -5a+10 = 0 \iff a = 2$

We can check the answer: if $a=2$ the polynomial becomes

$2x^2+2(2)x+5x+10 = 2x^2+9x+10$

And we're claiming that $-a=-2$ is a root of this polynomial:

$2(-2)^2+9(-2)+10 = 2\cdot 4 - 18 + 10 = 0$

5 0

3 years ago