All categories

2 years ago

4. Find the vertex, focus, and directrix of the parabola. Sketch its graph, showing the focus and the directrix.

Mathematics

1 answer:

valentina_108 [34]2 years ago

8 0

Answer:

vertex - (0,0)

focus - (0, 3/4)

directrix - 3/4

parabola- x^2=-3y

graph of equation:

You might be interested in

What are domain restrictions for this context

VikaD [51]

Answer:idk

Step-by-step explanation:I just got here

6 0

3 years ago

Assume that y varies directly with x. If y=9 when x=−3, find x when y=6.

Dafna1 [17]

Answer:-2

Step-by-step explanation:

8 0

3 years ago

Of all graduating students in a state college system, 50.5% of graduates identify as female, 36.4% of the students graduate with

motikmotik

Answer:

dsaf

Step-by-step explanation:

asdefsadfsafsdf

5 0

2 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

#SPJ4

3 0

1 year ago

Find X <br><br> Simplify answer type exact number or use radicals as needed

satela [25.4K]

On a right triangle, to find one missing side you can use this equation
a^2 + b^2 = c^2

a and b are the sides next to the right angle, and c is the hypotenuse (side not connected to right angle).

You first need to find the length of the dotted line before finding x. This is because to be able to use the above formula, you have to know the length of two out of three of the sides.

To solve the length of the dotted line, note that it also makes a triangle with the 5 unit line and the 5 √5 unit line. You can plug these numbers into the formula.
(5)^2+b^2=(5 √5)^2
25+b^2=125
b^2=100
b=10

Now that you know the length of the dotted line is 10 units, you can now solve for x

(20)^2+(10)^2=x^2
400+100=x^2
500=x^2
x= √500, which equals 22.361

5 0

3 years ago