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3 years ago

9

¿ sᴉɥʇ ǝʌlos noʎ uɐɔ

{2} = 225" alt=" {x}^{2} = 225" align="absmiddle" class="latex-formula">
¿ x puᴉɟ

2 answers:

VLD [36.1K]3 years ago

6 0

yes, i can solve it.

x = 15

☆o(^▽^)o☆

Ta-Da

UNO [17]3 years ago

3 0

Answer: Final Answer

x=15,x=−15

Step-by-step explanation:

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C is the answer 12 marbles and 20 marbles

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Subtract <br><br> \frac{3n+2}{n-4}-\frac{n-6}{n+4}

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3 years ago

Read 2 more answers

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3 years ago

Benecio worked 40 hours at his two jobs last week. He earned $20 per

miv72 [106K]

Answer:

25 hours on his week job and 15 hours on his weekend job

Steps

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3 years ago

Find the indicated limit, if it exists.

kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

<u>Calculus</u>

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Limit Property [Addition/Subtraction]: $\displaystyle \lim_{x \to c} [f(x) \pm g(x)] = \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)$

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}$

<u>Step 2: Find Right-Side Limit</u>

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^+} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} 5 - x = 5 - 5 = 0$

<u>Step 3: Find Left-Side Limit</u>

Substitute in function [Limit]: $\displaystyle \lim_{x \to 5^-} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ Since $\displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)$ , then $\displaystyle \lim_{x \to 5} f(x) = DNE$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

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3 years ago