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REY [17]
2 years ago
15

Find the value of y.

Mathematics
1 answer:
Elodia [21]2 years ago
8 0

Answer:

<h2><u><em>94°</em></u></h2>

Step-by-step explanation:

Find x

(180 - 36) : 2 =

72°

so angle 2x is 144°

sum of all interior angles = 720°

Find y

720 - 144 - 111 - 105 - 165 - 101 =

94°

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What is the equation of the line that is parallel to y-3x=2 and that passes through (6,1)?
Artemon [7]

Try this solution (analytic method):

1. if new line is parallel to the given one (y=3x+2) it means the new line has a form y=3x+b, where b - number.

2. In order to calculate 'b', it need to substitute the coordinates of point (6;1) into the equation of the new line:

1=3*6+b, ⇒ b=-17.

3. If to make up the equation of the new line:

y=3x-17

Answer: A

8 0
3 years ago
30 tens = ones<br> 30 tens = hundreds
Svetllana [295]

30 tens = 30 x 10 = 300

300 ones = 300 x 1 = 300

300 is your answer

30 tens = 30 x 10 = 300

3 hundreds = 3 x 100 = 300

3 is your answer

<em>~Rise Above the Ordinary</em>

4 0
3 years ago
I've been stuck on this for an hour. Can someone help?
kicyunya [14]
I cant read the price numbers which price numbers are there left
4 0
3 years ago
The sum of twelve times p and d
KIM [24]
<h3>Hey there! </h3><h3>"The sum of twelve times p and d" </h3><h3>Firstly, you could pull out your key terms for better understanding of the expression</h3><h3>Here's your key terms </h3>
  • Sum
  • (Of) twelve
  • Times
  • P and D
<h3>Let's find out what each term mean for setting up your problem , easier </h3>

Sum = add (+)

Twelve = 12

p & d = p & d (since they are <em><u>unknown numbers</u></em>)

SO, this means that your answer SHOULD look like this: 12p + d

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)


6 0
3 years ago
Find the fourth roots of i
antoniya [11.8K]

Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

<h3>Application</h3>

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

4 0
1 year ago
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