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mars1129 [50]
3 years ago
11

TRIPLE POINTS!!!! DUE TODAY!!!!

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Congruence?

Step-by-step explanation:

Maybe it's Transitive property of Congruence

It could be, idk

But I hoped this helped! :D

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Rewrite x - 2y = 8 using function notation.
Yanka [14]
x - 2y = 8 then it is y = 0.5x-4.

Hope I helped! ( Smiles )
8 0
4 years ago
What must be true to find the sum of a infinite sequence?
Georgia [21]

Answer:

The series must be decreasing, and the limit as the n-th term goes to infinity should be 0.

3 0
4 years ago
During a sale, 20-cent candy bars were sold at 3 for 50 cents. How much is saved on 9 bars?
Mazyrski [523]

Answer:

Step-by-step explanation:

$0.30

Step-by-step explanation:

1 bar of candy = $0.20

3 bars of candy = $0.50

To solve, multiply for both:

If you pay for each candy bar individually, they each cost $0.20. Multiply 9 with 0.20:

9 x 0.20 = $1.80

If you pay for the candy bars by 3's, they cost $0.50 each pack. Divide 9 with 3, then multiply by 0.50:

9/3 = 3

3 x 0.50 = $1.50

Subtract the total cost of the individual from the pack:

$1.80 - $1.50 = $0.30

. $0.30 is your answer.

8 0
3 years ago
The position of an object at time t is given by s(t) = 1 - 12t. Find the instantaneous velocity at t = 2 by finding the derivati
yulyashka [42]

The change of displacement with respect to time is defined as speed. Velocity is a vector quantity. The instantaneous velocity at t = 2 is -12.

<h3>What is velocity?</h3>

The change of displacement with respect to time is defined as Velocity. velocity is a vector quantity. It is a time-based component. Its standard unit is m/sec.

Given that the position of an object at time t is given by s(t) = 1 - 12t. Therefore, the velocity of the object can be written as,

V = ds/dt

   = d(1 - 12t)/dt

   = -12

s'(t) = -12

Now, the instantaneous velocity at t=2 is,

s'(2) = -12

Hence, the instantaneous velocity at t = 2 is -12.

To learn more about Velocity:

brainly.com/question/862972

#SPJ1

5 0
2 years ago
A 4 metre ladder is placed against a vertical wall.
Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

<em>hope it helps...</em>

<em>correct me if I'm wrong...</em>

4 0
3 years ago
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