Answer:
The number that goes in place of the question mark is 2.
Step-by-step explanation:
Let's solve it!
3x² + 12x - 24 = 0
First we can factor 3 out of each term:
x² + 4x - 8 = 0
Now we'll add 12 to both sides to complete the square:
x² + 4x + 4 = 12
And finish it off:
(x + 2)² = 12
So the answer to the question is 2
Bonus:
We can also now solve this for x:
(x + 2)² = 12
x = √12 - 2
x = 2√3 - 2
x ≈ 2 × ±1.732 - 2
x ≈ 1.464, -5.464
For this case we have the following equation:
We must clear the value of the variable "x" as a function of r, s and t:
If we multiply by "r" on both sides of the equation we have:
If we subtract "t" on both sides of the equation we have:
If we divide by "2" on both sides of the equation we have:
Thus, the value of the variable "x" is:
Answer:
Answer:
I think you wrote something wrong.
Step-by-step explanation:
If Alaina has $7 in her bank account and Joel had $48 in his Joel already has more then Alaina but I will attempt to teach you how to solve these types of problems.
for this example I'm giving Alaina 79 dollars.
First we know were starting with 79 dollars and increasing 6 dollars each day so the equation for this is; y = 6x + 79 that is Alaina's equation.
For Joel our equation will be; y = 8x + 48.
Since they already have 79 and 48 dollars in their bank we put those as our B in the equation cause they are our y-intercepts. (Y = mx + b) Next we know their increasing by 6 and 8 dollars a day so we make those our m. Once we have these equations we can plot them and see where the lines meet. (thats our answer) I plotted them on desmos graphing calculator.
They crossed at (15.5, 172) Which means it will take 16 days for Joel to catch up they will both have 172 dollars in the bank account on the 16th day.
Hope this helps!
It would be the first graph because the slope would be zero making it the smallest
Answer:
an = 4^(n-1)
Step-by-step explanation:
The three given terms have a common ratio of 4:
4/1 = 16/4 = 4
So, this can be described by the function for a geometric sequence:
an = a1×r^(n -1)
where an is the n-th term, a1 is the first term (1) and r is the common ratio (4).
an = 1×4^(n-1)
an = 4^(n -1) . . . . . simplified
