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s2008m [1.1K]
3 years ago
10

RSM was founded in 1996. From 1996 to 1997, the number of students in RSM doubled. From 1997 to 1998 the number of students doub

led again.
By what percent did the number of students increase from 1997 to 1998?
Mathematics
2 answers:
kaheart [24]3 years ago
3 0
To find the increase from 1997 to 1998, you could substitute in numbers and then determine the percent increase based on those numbers.

Ex: 500 to 1000 (96-97)
      1000 to 2000 (97-98)
Percent increase is (2000-1000)/1000 or 100% increase.

Testing another set of numbers will result in the same thing.

Ex: 200 to 400 (96-97)
      400 to 800 (97-98)
Percent increase is (800-400)400 or 100% increase.

The percent increase is 100%.
Neko [114]3 years ago
3 0

Answer:

The number of students increase from 1997 to 1998 by 100 %.

Step-by-step explanation:

Let x be the number of students in the year 1996.

According to the question,

The number of students on 1997 = 2x

Also, the number of students on 1998 = 4x

Thus, the percentage increase in the number of students from 1997 to 1998

=\frac{\text{the number of students on 1998-the number of students on 1997}}{\text{the number of students on 1997}}\times 100

=\frac{4x-2x}{2x}\times 100

=\frac{2x}{2x}\times 100

=100\%

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Veronika [31]

Answer:

p= kd^{2}u^{3}

Step-by-step explanation:

Using k as the constant of proportionality.

The expression that expresses the relationship : p varies jointly with the square of d and the cube of u.

Varies jointly means that p will change as 'd' and 'u' will change together with respect to their powers.

We get the expression as:

p= kd^{2}u^{3}

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3 years ago
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Serga [27]

Answer:

A)y=9x+5

Step-by-step explanation:

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3 0
2 years ago
ΔABC is dilated by a factor of 3 to produce ΔA'B'C'.
Rus_ich [418]

Answer:

Option B

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2 years ago
The Diagram shows the net of a square pyramid and its dimensions ​
Serjik [45]

<u>Answer:</u>

<h2>SA = 84 ft²</h2>

<u>Explanation:</u>

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