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2 years ago

1. A motorboat travels 196 meters in 20 seconds. What is the motorboat's unit rate of speed?

Mathematics

2 answers:

Grace [21]2 years ago

8 0

Answer:

9/4/5m/s

speed is equal to distance all over time. So196m/20s=9/4/5m/s

dezoksy [38]2 years ago

3 0

Answer:

196: 9.8

20: 1

x= 9.8 meters in 1 second

Step-by-step explanation:

This can be determined by following writing equal ratios that represent a word problem. Then, the denominator must be divided from the numerator to get the unit rate/ meters per second.

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For the past several years, the high school theater department has performed a musical in their auditorium. Each year since the

goblinko [34]

Answer:

D. The independent variable is the number of ticket price increases, and the dependent variable is the ticket sales.

Step-by-step explanation:

The wording, "the table shows A <em>with respect to</em> B" means that "B" is the independent variable. Here, "B" is "the number of times they have increased the price of the ticket." That is ...

the independent variable is the number of ticket price increases

5 0

2 years ago

The Slow Ball Challenge or The Fast Ball Challenge.

cupoosta [38]

Answer:

Fast ball challenge

Step-by-step explanation:

Given

Slow Ball Challenge

$Pitches = 7$

$P(Hit) = 80\%$

$Win = \$60$

$Lost = \$10$

Fast Ball Challenge

$Pitches = 3$

$P(Hit) = 70\%$

$Win = \$60$

$Lost = \$10$

Required

Which should he choose?

To do this, we simply calculate the expected earnings of both.

Considering the slow ball challenge

First, we calculate the binomial probability that he hits all 7 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 7$ --- pitches

$x = 7$ --- all hits

$p = 80\% = 0.80$ --- probability of hit

So, we have:

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

$P(7) =^7C_7 * 0.80^7 * (1 - 0.80)^{7 - 7}$

$P(7) =1 * 0.80^7 * (1 - 0.80)^0$

$P(7) =1 * 0.80^7 * 0.20^0$

Using a calculator:

$P(7) =0.2097152$ --- This is the probability that he wins

i.e.

$P(Win) =0.2097152$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 -0.2097152$

$P(Lose) = 0.7902848$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.2097152 * \$60 + 0.7902848 * \$10$

Using a calculator, we have:

$Expected = \$20.48576$

Considering the fast ball challenge

First, we calculate the binomial probability that he hits all 3 pitches

$P(x) =^nC_x * p^x * (1 - p)^{n - x}$

Where

$n = 3$ --- pitches

$x = 3$ --- all hits

$p = 70\% = 0.70$ --- probability of hit

So, we have:

$P(3) =^3C_3 * 0.70^3 * (1 - 0.70)^{3 - 3}$

$P(3) =1 * 0.70^3 * (1 - 0.70)^0$

$P(3) =1 * 0.70^3 * 0.30^0$

Using a calculator:

$P(3) =0.343$ --- This is the probability that he wins

i.e.

$P(Win) =0.343$

The probability that he lose is:

$P(Lose) = 1 - P(Win)$ ---- Complement rule

$P(Lose) = 1 - 0.343$

$P(Lose) = 0.657$

The expected value is then calculated as:

$Expected = P(Win) * Win + P(Lose) * Lose$

$Expected = 0.343 * \$60 + 0.657 * \$10$

Using a calculator, we have:

$Expected = \$27.15$

So, we have:

$Expected = \$20.48576$ -- Slow ball

$Expected = \$27.15$ --- Fast ball

<em>The expected earnings of the fast ball challenge is greater than that of the slow ball. Hence, he should choose the fast ball challenge.</em>

5 0

2 years ago

I need help on 16,17,18,19 please

aev [14]

Answer:

Obtuse stb stb a ad

Step-by-step explanation:

5 0

3 years ago

I’ve been trying sooo hard to get this and i can’t, please help

Greeley [361]

Should be 37 if you use Pythagorean theorem!

7 0

3 years ago

A $120,000, 5%, 200-day note dated June 6 is discounted on October 8. The discount period is how many days?

expeople1 [14]

June: 30-6=24
July: 31
August:31
September:30
October: 8
Total=24+31+31+30+8=124 days

Discount period:
The period of time between the date a bill of exchange is drawn and the date on which payment is due.

So discount period = 200-124=76 days

5 0

3 years ago