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Assoli18 [71]
2 years ago
14

What answers is. I don’t know

Mathematics
1 answer:
worty [1.4K]2 years ago
5 0

Answer:

d

Step-by-step explanation:

is the right answer

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1. Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).
Bond [772]

Answer:

1. Factor the expression using the two different techniques listed for Parts 1(a) and 1(b).

(a) Factor the given expression using the GCF monomial.

(b) Factor the given expression using the difference of squares.

DO NOT ANSWER UNLESS YOU CAN EXPLAIN THIS TO ME CORRECTLY

3 0
2 years ago
What is the value of minus 6 x cubed minus y squared minus 3 x y if if x = -2 and y = 4
Oksi-84 [34.3K]

Well, "minus 6 x cubed minus y squared minus 3 x y" translates to:

-6x^{2} -y^{2} -3xy

Then, if we insert the values for x and y, we get:

-6(-2)^{2} -(4)^{2} -3(-2)(4)

When we distribute and multiply:

144-16-24

And once we combine like terms:

104<em> is the answer</em>


8 0
3 years ago
Read 2 more answers
Prove that $5^{3^n} + 1$ is divisible by $3^{n + 1}$ for all nonnegative integers $n.$
Viktor [21]

When n=0, we have

5^{3^0} + 1 = 5^1 + 1 = 6

3^{0 + 1} = 3^1 = 3

and of course 3 | 6. ("3 divides 6", in case the notation is unfamiliar.)

Suppose this is true for n=k, that

3^{k + 1} \mid 5^{3^k} + 1

Now for n=k+1, we have

5^{3^{k+1}} + 1 = 5^{3^k \times 3} + 1 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k}\right)^3 + 1^3 \\\\ ~~~~~~~~~~~~~ = \left(5^{3^k} + 1\right) \left(\left(5^{3^k}\right)^2 - 5^{3^k} + 1\right)

so we know the left side is at least divisible by 3^{k+1} by our assumption.

It remains to show that

3 \mid \left(5^{3^k}\right)^2 - 5^{3^k} + 1

which is easily done with Fermat's little theorem. It says

a^p \equiv a \pmod p

where p is prime and a is any integer. Then for any positive integer x,

5^3 \equiv 5 \pmod 3 \implies (5^3)^x \equiv 5^x \pmod 3

Furthermore,

5^{3^k} \equiv 5^{3\times3^{k-1}} \equiv \left(5^{3^{k-1}}\right)^3 \equiv 5^{3^{k-1}} \pmod 3

which goes all the way down to

5^{3^k} \equiv 5 \pmod 3

So, we find that

\left(5^{3^k}\right)^2 - 5^{3^k} + 1 \equiv 5^2 - 5 + 1 \equiv 21 \equiv 0 \pmod3

QED

5 0
2 years ago
Adele Swam the length of the pool in 32.56 seconds. Alexandria swam the length of the pool in 29.4 seconds. How many seconds fas
Sati [7]

Answer

Find out how many seconds faster has Alexandria's time then Adele's time .

To proof

Let us assume that seconds faster has Alexandria's time then Adele's time be x.

As given in the question

Adele Swam the length of the pool in 32.56 seconds. Alexandria swam the length of the pool in 29.4 seconds.

Than the equation becomes

x = 32.56 - 29.4

x = 3.16 seconds

Therefore the 3.16 seconds faster has Alexandria's time then Adele's time .

Hence proved


7 0
3 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
jonny [76]
Answer: 11 2/15
Explanation: (3+7) (1/3+4/5)
10 + 17/15
10 + 1 2/15
11 2/15
5 0
3 years ago
Read 2 more answers
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