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Assoli18 [71]
2 years ago
14

What answers is. I don’t know

Mathematics
1 answer:
worty [1.4K]2 years ago
5 0

Answer:

d

Step-by-step explanation:

is the right answer

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Which of the following are solutions to the equation below?
Dovator [93]

Answer:

Apply quaratic equation

6 0
2 years ago
In each of the following ,make y the subject and hence find the value of y when a=2, b=3 ,and c=4.
zvonat [6]

Part i


\dfrac{2a-7}{6y} = \dfrac{3b-5}{2c}


y = \dfrac{ 2c(2a-7)}{6(3b-5)} = \dfrac{c(2a-7)}{9b-15}


Substituting,

y = \dfrac{4(2(2)-7)}{9(3)-15} = \dfrac{ -12}{12} = -1


Answer: -1


Part ii


I'm not sure that one's typed in correctly but I'll solve it as written.


3-34y + 2a = \dfrac{3b-5}{2c + 1}


34y  = 3+2a-\dfrac{3b-5}{2c + 1}


y = \frac 1 {34}\left(3+2a-\dfrac{3b-5}{2c + 1} \right)


We're not asked to simplify it so I wont. Substituting,


y = \frac 1 {34}\left(3+2(2)-\dfrac{3(3)-5}{2(4) + 1} \right) = \frac 1 {34}(7-4/9) = \dfrac{59}{306}


Answer: 59/306



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3 years ago
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I believe it is c sorry if i am wrong
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Answer:16 dollars per shirt

Step-by-step explanation:

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Help now pls bby pls
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Step-by-step explanation:

there are commas where they are supposed to be

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