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sleet_krkn [62]
2 years ago
8

What can spectroscopes tell us about a space object?

Physics
2 answers:
Ugo [173]2 years ago
7 0

Answer:

\huge\boxed{\sf Option \ 3}

Explanation:

<h2><u>Spectroscope:</u></h2>
  • The device used to tell the properties of the spectral lines in an electromagnetic spectrum is called spectroscope.
<h3> <u>Properties of spectroscope:</u></h3>
  • <u>For any space object, spectroscope tells:</u>
  1. Type of element the object is made of.
  2. Temperature of object.
  3. Chemical composition.
  4. Speed
  5. Magnetic and electric field.
  • Spectroscope also can tell the light intensity and their wavelength.

\rule[225]{225}{2}

UNO [17]2 years ago
4 0

Answer:

The answer is C.

Explanation:

  • Spectroscopy can be very useful in helping scientists understand how an object like a black hole, neutron star, or active galaxy produces light, <u>how fast it is moving, and what elements it is composed of.</u>
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Calculate the Energy (E) in joules for that wavelength and record it in the table below. Remember that E = HF, where h the Planc
Viefleur [7K]

In that formula for Energy, 'F' is the frequency of the photon.
But <u>Frequency = (speed)/(wavelength)</u>, so we can write the
Energy formula as
                                 E = h c / (wavelength) .

So the energy, in joules, of a photon with that wavelength, is . . .

                                 E = (6.6 x 10⁻³⁴) x (3 x10⁸) / (that wavelength)

                                    = <em>(1.989 x 10⁻²⁵) / (that wavelength, in meters) .</em>


5 0
3 years ago
If you push a crate horizontally with 100 N across a 10 m factory floor and the friction between the crate and the floor is a st
erik [133]

Answer:

300 J

Explanation:

First of all, we need to calculate the net force acting on the crate, which is given by:

F_{net} = F-F_f

where

F = 100 N is the horizontal push

F_f = 70 N is the force of friction

Substituting,

F_{net}=100 - 70 = 30 N

Now we can calculate the net work done on the crate:

W=F_{net}d

where

d = 10 m is the displacement

Substituting,

W=(30)(10)=300 J

According to the work-energy theorem, the kinetic energy gained by the crate is equal to the work done on it: therefore, the answer is 300 J.

4 0
3 years ago
A uniform brick of length 25 m is placed over
Harlamova29_29 [7]

The system of two rods will lie on the table as show in the figure

The center of first rod will lie exactly at the edge of first rod and then the center of mass of two combined rods will lie at the edge of the table.

So now the whole system will rest on the rod and it will not tipping off.

Since both rods are identical so we can say that the system will have its center of mass at the mid point on the line joining the two centers

So the value of x will be at mid point of line joining the two points on rod

x = \frac{12.5}{2} = 6.25 cm

So total length over the edge will be given as

L = 6.25 cm + 12.5 cm = 18.75 cm

3 0
3 years ago
Heating up a reaction speeds up the rate of the reaction because...
kherson [118]

Answer:

A.

Explanation:

more heat = heat energy becomes more kinetic energy = more particle collision

3 0
3 years ago
Read 2 more answers
To keep the calculations fairly simple, but still reasonable, we shall model a human leg that is 92.0 cm long (measured from the
lorasvet [3.4K]

Answer:

Xc = 64.27 cm, Yc = 0 cm, Xc = 27.73 cm, Yc = 18.27 cm

Explanation:

A human leg is 92 cm long equally divided into two parts (upper leg and lower leg) that is both are 46 cm long

M1 = 8.35 kg

M2 = 5.50 kg

A. Starting from hip joint, when the leg is placed horizontally, the X coordinate of centre of mass will be

Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50 x 92) / 8.35 + 5.50

( here we took x2 = 92 cm because we are measuring length from the hip joint, that means length at hip joint is 0 and at the foot 92 cm)

Xc = 890.1 / 13.85

Xc = 64.27 cm

B. Yc = (y1m1 + y2m2) / m1 + m2

Yc = (0x8.35 + 0x5.50) / 8.35 + 5.50

( here y1 and y2 are 0 because the leg is placed horizontally that means in X direction so none of the leg component is in Y direction)

Yc = 0 cm

C. Xc = (m1x1 + m2x2) / m1 + m2

Xc = (8.35x46 + 5.50x0) / 8.35 + 5.50

(here x2 is taken 0 because the other half leg is bent vertically that means it is in Y direction so its X component is 0)

Xc = 384.1 / 13.85

Xc = 27.73 cm

D. Yc = (m1y1 + m2y2) / m1 + m2

Yc = (8.35x0 + 5.50x46) / 8.35 + 5.50

(here y1 is zero because the upper leg is in X direction and y2 is taken 46 cm because starting measuring from hip joint 46 cm of length of lower leg is in Y direction)

Yc = 253/13.85

Yc = 18.27 cm

7 0
3 years ago
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