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Semenov [28]
3 years ago
15

physics major is cooking breakfast when he notices that the frictional force between the steel spatula and the Dry Steel frying

pan is only 0.200 N. Knowing the coefficient of kinetic friction between the two materials (0.3), he quickly calculates the normal force. What is it (in N)?
Physics
1 answer:
givi [52]3 years ago
8 0

Answer:0.667 N

Explanation:

Given

It is noticed that Frictional Force is 0.2 N

Coefficient of kinetic Friction \mu _k=0.3

We know Friction Force is given by

f_r=\mu _k\times Normal\ reaction

therefore

0.2=\mu _k\times N

0.2=0.3\cdot N

N=\frac{0.2}{0.3}

N=0.667 N

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When time is measured in​ days, the decay constant for a particular radioactive isotope is 0.16. Determine the time required for
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Answer:

The time take is  t = 1.3964 \ days

Explanation:

From the question we are told that

    The decay constant is  \lambda  = 0.16

     The percentage fall is  c =  0.80

The equation for radioactive decay is mathematically represented as

               N(t) =  N_o  * e^{- \lambda t  }

Where is N(t) is the new amount of the new the isotope while N_o is the original

At initial  N_o =  100%  = 1

At N(t ) =  80%  = 0.80  

       0.80 =  1 * e^{- 0.16 t }

=>     -0.223 =  -0.16 t

=>     t = 1.3964 \ days

5 0
3 years ago
Read 2 more answers
A 300 cm rope under a tension of 120 N is set into oscillation. The mass density of the rope is 120 g/cm. What is the frequency
Vikki [24]

Answer:

Explanation:

f = \sqrt{T/(m/L)} / 2L

T = 120 N

L = 3.00 m

(m/L) = 120 g/cm(100 cm/m / 1000 g/kg) = 12 kg/m

                                                  (wow that's massive for a "rope")

f = \sqrt{120/12} /(2(3)))

f = \sqrt{10\\}/6 = 0.527 Hz

This is a completely silly exercise unless this "rope" is in space somewhere as the weight of the rope (353 N on earth) far exceeds the tension applied.

A much more reasonable linear density would be 120 g/m resulting in a frequency of √1000/6 = 5.27 Hz on a rope that weighs only 3.5 N

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2 years ago
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Paha777 [63]

Answer:

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Explanation:

First we need to convert the miles into meters, as the demanded result should be in meters.

1 mile = 1,609.34 meters

Also, 6.5 minutes should be converted into seconds.

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6.5 x 60 = 390 seconds

Now we need to divide the miles with the seconds to see how much meters have been run in a second.

1,609.34 / 390 = 4.13 meters

The suggested meters now should be divided with the distance run in one second.

400 / 4.13 = 96.85 seconds

So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.

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