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emmainna [20.7K]
2 years ago
6

By how much would 1500j of heat energy raise the temperature of 0.50kg of aluminum​

Physics
1 answer:
valentinak56 [21]2 years ago
7 0

pls what is the specific heat capacity of water

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An experimental 1500-kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. What is the
stepladder [879]

Answer:

363000 J or 363 kJ

Explanation:

Because the car is not rotating, it has no rotational kinetic energy. Its kinetic energy is then simply

\frac{1}{2} mv^2 = \frac{1}{2}\times1500\times22^2 = 363000 \text{ J}

8 0
4 years ago
What element from the periodic table rhymes with extreme
jonny [76]
Halite or sulfur or gold or silver
8 0
4 years ago
What minimum speed must an electron have to excite the 492-nm-wavelength blue emission line in the hg spectrum?
mezya [45]
The energy required by the excitation of the line is:
ΔE = hν = hc / λ
where:
ΔE = energy difference
h = Planck constant 
ν = line frequency
c = speed of light
λ = line wavelength

The energy difference must be supplied by the electron, supposing it transfers all its kinetic energy to excite the line:
\Delta E =  \frac{1}{2} m v^{2}

Therefore, 
\frac{1}{2} m v^{2} =  \frac{hc}{\lambda}

And solving for v we get:
v =  \sqrt{ \frac{2hc}{m\lambda} }

Plugging in numbers (after trasforing into the correct SI units of measurement):
v = \sqrt{ \frac{(2)(6.6 \cdot  10^{-34})(3 \cdot  10^{8})  }{(9.11 \cdot  10^{-31})(4.92 \cdot  10^{-7}) } }
=9.4 · 10⁵ m/s

Hence, the electron must have a speed of 9.4 · 10<span>⁵ m/s in order to excite the <span>492nm</span> line.</span>
5 0
3 years ago
A car accelerated from rest in 3.07s. During this time, the car went 46m forward. What was its acceleration?
kari74 [83]
Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
8 0
3 years ago
Calculate the ph of hydronium ions in a 0.000 01 M solution of the strong acid HI.
quester [9]

Answer:

D. 5

Explanation:

\mathbf{pH=-log_{10}[H^{+}]}

The above formula is used to find pH of any solution. For that you require the concentration of \textrm{H}^{+} or hydronium ion (\textrm{H}_{3}\textrm{O}^{+}) in the solution. Concentration should be in molarity (M) to get the pH.

The concentration of \textrm{H}^{+} ion is given as 0.00001 M or 10^{-5} M.

Substituting the value of \textrm{H}^{+} ion in the formula:

\textrm{pH}=- \textrm{log}_{10}[10^{-5}]

\textrm{pH}=-(-5)\textrm{log}_{10}[10]

\textrm{pH}=-(-5)(1)

\therefore\mathbf{pH=5}

(NOTE : Some logarithmic properties

\mathbf{log_{b}(b)=1}\\ \mathbf{log_{b}(a^{c})=c \cdot log_{b}(a)}

here 'b' is called the base of log and '\mathbf{a^{c}}' is called dthe argument of log. In the solution the base is '10' and the argument is \mathbf{H^{+}})

3 0
3 years ago
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