Answer:
363000 J or 363 kJ
Explanation:
Because the car is not rotating, it has no rotational kinetic energy. Its kinetic energy is then simply

Halite or sulfur or gold or silver
The energy required by the excitation of the line is:
ΔE = hν = hc / λ
where:
ΔE = energy difference
h = Planck constant
ν = line frequency
c = speed of light
λ = line wavelength
The energy difference must be supplied by the electron, supposing it transfers all its kinetic energy to excite the line:

Therefore,

And solving for v we get:

Plugging in numbers (after trasforing into the correct SI units of measurement):

=9.4 · 10⁵ m/s
Hence, the electron must have a speed of
9.4 · 10<span>
⁵ m/s in order to excite the <span>492nm</span> line.</span>
Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
Answer:
D. 5
Explanation:
![\mathbf{pH=-log_{10}[H^{+}]}](https://tex.z-dn.net/?f=%5Cmathbf%7BpH%3D-log_%7B10%7D%5BH%5E%7B%2B%7D%5D%7D)
The above formula is used to find pH of any solution. For that you require the concentration of
or hydronium ion (
) in the solution. Concentration should be in molarity (M) to get the pH.
The concentration of
ion is given as 0.00001 M or
M.
Substituting the value of
ion in the formula:
![\textrm{pH}=- \textrm{log}_{10}[10^{-5}]](https://tex.z-dn.net/?f=%5Ctextrm%7BpH%7D%3D-%20%5Ctextrm%7Blog%7D_%7B10%7D%5B10%5E%7B-5%7D%5D)
![\textrm{pH}=-(-5)\textrm{log}_{10}[10]](https://tex.z-dn.net/?f=%5Ctextrm%7BpH%7D%3D-%28-5%29%5Ctextrm%7Blog%7D_%7B10%7D%5B10%5D)


(NOTE : Some logarithmic properties

here 'b' is called the base of log and '
' is called dthe argument of log. In the solution the base is '10' and the argument is
)