Answer:108
Step-by-step explanation:
Answer:
y = -5x/4 - 8
Two lines that are perpendicular have slopes that are opposite reciprocals.
Since the slope of the given line is 4/5, the opposite reciprocal of that is -5/4. So the equation has a slope of -5/4.
Since we know the coordinate of a point of the other equation, we can plug that into the point-slope form equation y - y1 = m(x - x1):
y - 2 = -5/4(x-(-8))
Simplify:
y - 2 = -5/4(x+8)
y - 2 = -5x/4 - 10
So the equation in slope-intercept form is:
(x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb R
4x-6y=-26
-2x+3y-13
x=-13/2+3/2y
4(-13/2+3/2y) - 6y=-26
y in mathbb R
x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb
1. x = -4y ---> y = (-1/4)x
slope = -1/4. y-intercept = (0,0)
2. y = -2x + 4
3. y = (1/3)x - 1
1. Re-write your equation so that x is on the right and y is on the left:
x = -4y ---> y = (-1/4)x
2. y-intercept = (0,4) ----> P1
x-intercrpt = (2,0) ----> P2
slope m = (y2 - y1) / (x2 - x1)
= (0 - 4)/(2 - 0)
= -2
therefore, y - y1 = mx - x1 ---> y - 4 = -2x
or y = -2x + 4
3. y-intercept = (0,-1)
x-intercept = (3,0)
m = (0 - (-1)) / (3 -0) = 1/3
y - (-1) = (1/3)x - 0 ---> y = (1/3)x - 1
604
add them together using collum method
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