C = 220T + 1890.
Solve the equation for T.
220T = C - 1890
T = C/220 - 8.6
The steel produced is expected to be sold at a price of $310 per ton.
310 $/ton is a rate or slope. Write a linear equation where x is tons of steel produced and y is selling price of the steel.
y = 310x
Write and solve an equation to find the amount of steel produced if the selling price is equal to the cost of production.
* Here, note that the cost of production and tons of steel in the first equation is in the millions. The equation we just wrote for the selling price was in x tons of steel. This only matters in regards to the units you specify because; million/million = 1
The unit multiplier of all variables must be specified as same. Either everything is in millions or not.
Here, I'll leave everything in millions, change x (tons of steel) to T (mill tons steel) and "y" to "S" in million dollars selling price.
S = 310T
Set equal to Cost equation.
220T + 1980 = 310T
Solve for T, million tons of steel produced.
1980 = 310T - 220T
1980 = 90T
T = 1980/90
T = 22 million tons steel produced
Answer:
Can't see the picture because old computer but isn't 16 minus 17 = -1 (negative 1)
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
12568*.45 = 5655.6
c is best answer here
Answer:
y= 3x -4
Step-by-step explanation:
The equation of a line can be written in the form of y=mx +c, where m is the slope and c is the y-intercept. This is also known as the slope-intercept form.

Since the given equation is in the slope-intercept form, we can identify its slope from the coefficient of x.
Slope= -⅓
The product of the slopes of perpendicular lines is -1.
Slope of perpendicular line


= 3
Thus, the equation of the perpendicular line is given by:
y= 3x +c
Substitute a pair of coordinates that the line passes through to find the value of c.
When x= 3, y= 5,
5= 3(3) +c
5= 9 +c
<em>Minus 9 on both sides:</em>
c= 5 -9
c= -4
Hence, the equation of the perpendicular line is y= 3x -4.
Additional:
For more questions on equation of perpendicular lines, do check out the following!