1/ab + a^2/b^2 find the sum?

Mathematics

1 answer:

maxonik [38]1 year ago

7 0

$\dfrac 1{ab} + \dfrac{a^2}{b^2}\\\\\\=\dfrac{b+a^3}{ab^2}\\\\\\=\dfrac{a^3 +b}{ab^2}$

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Point A is located at negative 5 over 8 and point B is located at negative 2 over 8. What is the distance between points A and B

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<h2>Answer:</h2>

Option: A is the correct answer.

A. negative 5 over 8 minus negative 2 over 8 = negative 3 over 8; therefore, the distance from A to B is absolute value of negative 3 over 8 equals 3 over 8 units.

<h2>Step-by-step explanation:</h2>

The location of Point A is : A(-5/8)

and Point B is located at : B(-2/8)

We know that when two points lie over a number line then the distance between the two points is the absolute difference between the two points.

If A is located at a.

and B is located at b.

Then the distance between A and B is given by:

|a-b|

Hence, here the distance between A and B is given by:

$|\dfrac{-5}{8}-(\dfrac{-2}{8})|=|\dfrac{-5}{8}+\dfrac{2}{8}|=|\dfrac{-3}{8}|=\dfrac{3}{8}\\\\i.e.\\\\\text{Distance between A and B is}=\dfrac{3}{8}\ \text{units}$