1/ab + a^2/b^2 find the sum?

Mathematics

1 answer:

maxonik [38]1 year ago

7 0

$\dfrac 1{ab} + \dfrac{a^2}{b^2}\\\\\\=\dfrac{b+a^3}{ab^2}\\\\\\=\dfrac{a^3 +b}{ab^2}$

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Please help immediately

Burka [1]

Answer: $f'(1)=\dfrac{4}{2y+1}$

Step-by-step explanation:

To find the tangent, you need to find the derivative with respect to x.

Then substitute x = 1 into the derivative.

Given: 0 = 2x² - xy - y²

Derivative: 0 = 4x - y' - 2yy'

Solve for y': 2yy' + y' = 4x

y'(2y + 1) = 4x

$y'=\dfrac{4x}{2y+1}$

$\text{Substitute x = 1:}\quad y'(1)=\dfrac{4}{2y+1}$

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3 years ago

Use the discriminant to determine how many real number solutions exist for the quadratic equations -4j+3j-28=0

aleksandr82 [10.1K]

the correct equation is
- 4j² + 3j - 28 =0

ax² + bx + c,
a = -4, b=3 c =- 28.
The discriminent D = b² - 4.a.cD = 3² - 4(-4)(-28)D = -439
If D ≥ 0 there are either 2 roots or one double if = 0)if D< 0, there are no real roots (but 2 imaginary roots)Since D < 0, then there is no real roots
The answer there is no real roots

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3 years ago

How do you Graph y-3=1/3(x+1)

jekas [21]

Answer:

You can find the point of intersection of the line with the y-axis and the the point of intersection of the line with the x-axis. See the graph attached.

Step-by-step explanation:

Find the intersection with the y-axis. Substitute $x=0$ into the equation and solve for y: