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Brrunno [24]
2 years ago
13

Help me help me help me help me ​

Mathematics
1 answer:
Nitella [24]2 years ago
7 0

Answer:

1. 4/12, 3/9, 2/6, 5/15

2. 4/8, 8/16, 6/12

3. 2/8, 4/16, 3/12

4. 6/8, 9/12, 4/16

Step-by-step explanation:

I'm assuming your question is about all 4 problems shown so I'll explain how to solve all of them.

1. The question is asking you to find an equivalent fraction to 1/3. The easiest way to do this is to reduce all of the options given.

To reduce fractions, first determine if the numerator and denominator share any factors. If they do, divide both terms by the shared factors until you no longer get whole numbers.

Step 1: reduce answer choices

6/16 = 3/8 (done by dividing both terms by 2)

4/10 = 2/5 (divide both by 2)

3/8 = 3/8 (fully reduced)

2/5 = 2/5 (fully reduced)

4/12 = 1/3 (divide both by 4)

5/10 = 1/2 (divide both by 5)

1/2 = 1/2 (fully reduced)

3/9 = 1/3 (divide both by 3)

2/6 = 1/3 (divide both by 2)

5/15 = 1/3 (divide both by 5)

3/8 = 3/8 (fully reduced)

3/4 = 3/4 (fully reduced)

2. This question is solved the same way as question 1.

Step 1: reduce answer choices

2/5 = 2/5

6/9 = 2/3

4/8 = 1/2

3/9 = 1/3

8/16 = 1/2

8/10 = 4/5

7/12 = 7/12

6/12 = 1/2

3. This question is solved the same way as questions 1 and 2.

Step 1: reduce answer choices

3/8 = 3/8

2/8 = 1/4

4/9 = 4/9

2/7 = 2/7

4/16 = 1/4

10/14 = 5/7

6/9 = 2/3

3/12 = 1/4

4. This question is solved the same way as questions 1, 2, and 3.

Step 1: reduce answer choices

6/8 = 3/4

4/9 = 4/9

4/6 = 2/3

9/12 = 3/4

10/12 = 5/6

6/9 = 2/3

12/16 = 3/4

7/9 =7/9

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Two right triangles are shown. First, find the missing leg of the triangle on the right. Then you have two lengths to use to fin
jasenka [17]

Answer:

x = 30m

Step-by-step explanation:

<u>GIVEN :-</u>

There are 2 right-angled triangles.

In the triangle on the right side ,

  • Hypotenuse = 26m
  • Base = 10m

In the triangle on the left side ,

  • Base = 18m

<u>TO FIND :-</u>

  • Length of the common perpendicular to both triangles.
  • Length of the hypotenuse of the triangle on the left side.

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

  • Hypotenuse = \sqrt{Base^2 + Perpendicular^2}.
  • Perpendicular = \sqrt{Hypotenuse^2 - Base^2}

<u>SOLUTION :-</u>

In the triangle on the right side ,

Perpendicular = \sqrt{26^2 - 10^2} = \sqrt{676 - 100} = \sqrt{576} = 24m

⇒ Perpendicular of the triangle on right side = Perpendicular of the triangle on left side.

In the triangle on the left side ,

Hypotenuse = \sqrt{24^2 + 18^2} = \sqrt{576 + 324} = \sqrt{900} = 30m

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3 0
3 years ago
What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
galina1969 [7]
The answer is:  " 11 " .
____________________________________________________
            →     " x  =  11  "  .
____________________________________________________
Explanation:
____________________________________________________
Set up the ratio/ proportion as a fraction:

6 cm / 48 cm = 5 cm / (3x + 7) ; 

→ The "cm" units cancel out; since:  "cm/cm = 1 " ; 

→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) =  " 1/8 " ; 

→ Rewrite as:  \frac{1}{8} = \frac{5}{3x + 7} ;

Now, we can "cross-multiply" :
__________________________________________________

<u>Note</u>:  Given: \frac{a}{b} = \frac{c}{d} ;  ad = bc ; 
              {b\neq 0 ;  d \neq 0} .
__________________________________________________
 
As such:      
 
    1 * (3x + 7) = 8 * 5 ;

   →  3x + 7 = 40 ; 

Subtract "7" from each side of the equation:

   →  3x + 7 − 7 = 40 <span>− 7 ; 
</span>
to get:  

   → 3x = 33 ; 

Now, divide each side of the equation by "3" ; 
   to isolate "x" on one side of the equation; & to solve for "x" ; 

   →  3x / 3 = 33 / 3 ; 

to get: 
____________________________________________________
  
   →    " x = 11 " .
____________________________________________________
   →   The answer is:  " 11 " .
____________________________________________________
4 0
3 years ago
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