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3 years ago

What is the radius of the circle given by the equation below?

Mathematics

1 answer:

lapo4ka [179]3 years ago

3 0

Answer:

A. 3

Step-by-step explanation:

Hello

X^2 + 8X + (8/2)^2 + Y^2 + 14Y + (14/2)^2 = (8/2)^2 + (14/2)^2-56

(X+4)^2 + (Y+7)^2 = 16 + 49 - 56

(X+4)^2 + (Y+7)^2 = 9

Then

The radius for that circle is 3

Best regards

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3 years ago

A rectangle is 9 ft long and 40 in. wide. What is it’s area in square feet?

vladimir1956 [14]

<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ 40 inches = 3.33333

Area = length x width

Substitute the values:

Area = 9 x 3.33333

Solve:

Area = 30ft^2

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3 years ago

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A survey in one middle school showed that 4 out of 9 students help cook meals at home. Predict how many out of the 720 students

valentinak56 [21]

Answer:

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Step-by-step explanation:

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2 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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3 years ago

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torisob [31]

195 is the answer because you replace x with 10

Step-by-step explanation:

825-630=195

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