Answer:

Step-by-step explanation:
We are given that
Length of rope=l=160 feet
Radius of quadrant of circle=r=160 feet
We have to find the maximum grazing area of the cow.
We know that
Area of quadrant of circle=
Where 
Using the formula
Area grazed by cow=
Area grazed by cow=
In statistics, the number of degrees of freedom is the number of values in the final calculation of a statistic that are free to vary.
The number of independent ways by which a dynamic system can move, without violating any constraint imposed on it, is called number of degrees of freedom.
In other words, the number of degrees of freedom can be defined as the
minimum number of independent coordinates that can specify the position
of the system completely.
<span>
The degree of freedom represents the number of ways in which the expected classes are free to vary in the chi-square goodness-of-fit test.</span>
Given:
The equation of a line is:

The line is dilated by factor 3.
To find:
The result of dilation.
Solution:
The equation of a line is:

For
,




For
,




Divide both sides by 2.


The given line passes through the two points A(0,5) and B(2,2).
If the line dilated by factor 3 with origin as center of dilation, then

Using this rule, we get


Similarly,


The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:




Multiply both sides by 2.



Therefore, the equation of the line after the dilation is
.
Answer:
Step-by-step explanation:
The square root of a number is multiplying that number by its self so like 2² which is 2 squared. the answer would be 2 x 2 = 6 hope this helps!