Answer: the height in inches, of the pile after 3 weeks is 34 11/12 inches
Step-by-step explanation:
Each consecutive week for the next 5 weeks the height of pile increase by 8 7/12 inches. Converting 8 7/12 inches to improper fraction, it becomes 103/12 inches. The height is increasing in an arithmetic progression. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = 17 3/4= 71/4 inches
d = 103/12 inches
n = 3 weeks
the height in inches, of the pile after 3 weeks, T3. Therefore,
T3 = 71/4 + (3 - 1)103/12
T3 = 71/4 + 2 × 103/12 = 71/4 + 103/6
T3 = 419/12 inches = 34 11/12 inches
Step-by-step explanation:
How are we supposed to help...?
The anwser is 90 because its 90 degree angle
Answer:
1 And 3
Step-by-step explanation:
If ZM is an obtuse angle (greater than 90), then ZM and ZP will not add up to 90.
If ZP is 120, then ZM and ZP will not add up to 90.
There are multiple contradicting statements within this problem, as noted above.
Hope this helps!
