Can somebody help me find the zeroes for this, algebraically?
1 answer:
To solve this algebraically, you can first factor out a 3:
Then, you can factor (I'm using guess and check) and my answer is -4 and 2:
From here on, finding 0s is very easy. You just solve for x in the parentheses. So, the 0s are when x = 4, and x = -2. Remember, (4-4) = 0, and (-2+2) = 0, that's what you want.
Then, you can factor (I'm using guess and check) and my answer is -4 and 2:
From here on, finding 0s is very easy. You just solve for x in the parentheses. So, the 0s are when x = 4, and x = -2. Remember, (4-4) = 0, and (-2+2) = 0, that's what you want.
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Step-by-step explanation:
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Answer:
The probability that at least 280 of these students are smokers is 0.9664.
Step-by-step explanation:
Let the random variable <em>X</em> be defined as the number of students at a particular college who are smokers
The random variable <em>X</em> follows a Binomial distribution with parameters n = 500 and p = 0.60.
But the sample selected is too large and the probability of success is close to 0.50.
So a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:
1. np ≥ 10
2. n(1 - p) ≥ 10
Check the conditions as follows:
Thus, a Normal approximation to binomial can be applied.
So,
Compute the probability that at least 280 of these students are smokers as follows:
Apply continuity correction:
P (X ≥ 280) = P (X > 280 + 0.50)
= P (X > 280.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that at least 280 of these students are smokers is 0.9664.