Can somebody help me find the zeroes for this, algebraically?
1 answer:
To solve this algebraically, you can first factor out a 3:
Then, you can factor (I'm using guess and check) and my answer is -4 and 2:
From here on, finding 0s is very easy. You just solve for x in the parentheses. So, the 0s are when x = 4, and x = -2. Remember, (4-4) = 0, and (-2+2) = 0, that's what you want.
Then, you can factor (I'm using guess and check) and my answer is -4 and 2:
From here on, finding 0s is very easy. You just solve for x in the parentheses. So, the 0s are when x = 4, and x = -2. Remember, (4-4) = 0, and (-2+2) = 0, that's what you want.
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The space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
<h3>What is a cone?</h3>It is defined as the three-dimensional shape in which the base is a circular shape and if we go from circular base to top the diameter of the circle reduces and at the vertex, it becomes almost zero.
We know the volume of the cylinder is given:
r = 10/2 = 5 FT
h = 12 FT
V = 300π cubic FT
Volume of the cone:
v = 100π cubic FT
Space is inside the cylinder but outside the cone = 300π - 100π
= 200π cubic FT
= 628.32 cubic FT
Thus, the space is inside the cylinder but outside the cone is 200π cubic FT or 628.32 cubic FT.
Learn more about the cone here:
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