9514 1404 393
Answer:
2√30 ∠-120°
Step-by-step explanation:
The modulus is ...
√((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30
The argument is ...
arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle
The polar form of the number can be written as ...
(2√30)∠-120°
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<em>Additional comments</em>
Any of a number of other formats can be used, including ...
(2√30)cis(-120°)
(2√30; -120°)
(2√30; -2π/3)
2√30·e^(i4π/3)
Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).
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At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)
Answer:
A. thats the answer
Step-by-step explanation:
carry on learning
Y=-2x+0 reason: rise over run as you can see in the graph -2 rise (drop) and -1 run and b=0 y intercept
Answer:
B
Step-by-step explanation:
The end behavior of a function is how the graph behaves as it approaches negative and positive infinity.
Let's take a look at each end.
As x approaches negative infinity:
As x approaches the left towards negative infinity, we can see that the graph is shooting straight upwards.
Therefore, as
, our function f(x) is increasing and increasing up towards positive infinity.
Therefore, the end behavior at the left will be:

As x approaches (positive) infinity:
As x approaches the right towards positive infinity, we can see the that graph is also shooting straight upwards.
Therefore, the end behavior will be exactly the same. As x approaches positive infinity, f(x) <em>also</em> approaches positive infinity.
Therefore, the end behavior at the right will be:

Therefore, our answer is B.