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EastWind [94]
3 years ago
8

Which correctly Applies the distributaries property to show an equivalent expression to (-2.1)(3.4)

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

(–2.1)(3) + (–2.1)(0.4)

Step-by-step explanation:

It's D

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Write the complex number in polar form:
emmasim [6.3K]

9514 1404 393

Answer:

  2√30 ∠-120°

Step-by-step explanation:

The modulus is ...

  √((-√30)² +(-3√10)²) = √(30 +90) = √120 = 2√30

The argument is ...

  arctan(-3√10/-√30) = arctan(√3) = -120° . . . . a 3rd-quadrant angle

The polar form of the number can be written as ...

  (2√30)∠-120°

_____

<em>Additional comments</em>

Any of a number of other formats can be used, including ...

  (2√30)cis(-120°)

  (2√30; -120°)

  (2√30; -2π/3)

  2√30·e^(i4π/3)

Of course, the angle -120° (-2π/3 radians) is the same as 240° (4π/3 radians).

__

At least one app I use differentiates between (x, y) and (r; θ) by the use of a semicolon to separate the modulus and argument of polar form coordinates. I find that useful, as a pair of numbers (10.95, 4.19) by itself does not convey the fact that it represents polar coordinates. As you may have guessed, my personal preference is for the notation 10.95∠4.19. (The lack of a ° symbol indicates the angle is in radians.)

6 0
3 years ago
Find each quotient and express it in rectangular form.
uranmaximum [27]

Answer:

A. thats the answer

Step-by-step explanation:

carry on learning

4 0
2 years ago
Divide 20m^2n^3 - 10m^2n by 5mn
Sonja [21]

\frac{20 {m}^{2} {n}^{3}  - 10 {m}^{2}n  }{5mn}  \\  =   \frac{5mn(4m {n}^{2} - 2m) }{5mn}  \\  = 4 {m}^{2} n - 2m \\  = 2m(2mn - 1)

Hope this helps. - M
6 0
3 years ago
What is the standard form for the graph?
Novosadov [1.4K]
Y=-2x+0 reason: rise over run as you can see in the graph -2 rise (drop) and -1 run and b=0 y intercept
3 0
2 years ago
Plz help! what is the end of behavior of f(x)?
Tanzania [10]

Answer:

B

Step-by-step explanation:

The end behavior of a function is how the graph behaves as it approaches negative and positive infinity.

Let's take a look at each end.

As x approaches negative infinity:

As x approaches the left towards negative infinity, we can see that the graph is shooting straight upwards.

Therefore, as x\rightarrow-\infty, our function f(x) is increasing and increasing up towards positive infinity.

Therefore, the end behavior at the left will be:

\text{As } x\rightarrow-\infty, f(x)\rightarrow\infty

As x approaches (positive) infinity:

As x approaches the right towards positive infinity, we can see the that graph is also shooting straight upwards.

Therefore, the end behavior will be exactly the same. As x approaches positive infinity, f(x) <em>also</em> approaches positive infinity.

Therefore, the end behavior at the right will be:

\text{As } x\rightarrow \infty, f(x)\rightarrow \infty

Therefore, our answer is B.

5 0
2 years ago
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