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denis-greek [22]
2 years ago
11

X

Mathematics
1 answer:
natta225 [31]2 years ago
3 0

Based on the figures given in the table, the rate of change of the function is b. 5.

<h3>What is the function's rate of change?</h3>

This can be found as:

= (Y₂ - Y₁) / (X₂ - X₁)

Use points:

(0, 1/2) and (1, 5/2)

Solving gives:

= (5/2 - 1/2) / (1 - 0)

= 5

Find out more on the rate of change at brainly.com/question/25184007.

#SPJ1

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Felipe is working to find the quotient of 6 and 3/4
Natalka [10]

Answer:

Felipe's answer is 8.

6 divided by 3/4

= 6 * 4/3

= 24/3

= 8

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Round 126,945 to the nearest ten thousand
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126,945 to the nearest ten thousand is 130,000.
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Write the expression (4x-2)•6(2x+ 7) in the ax2+bx+c What are the values of the coefficient
tresset_1 [31]
The values of the coefficient are ax^2+bx+c=

48x^2-24x+84 and A= 48, B=-24, C=84.

(4x-2)•6(2x+7)=

6•2x+ 6•7

(4x-2)(12x+42)=

4x•12x= 48x^2 4x•42= 168.

-2•12x= -24x -2•42=-84

48x^2-24x+168-84=

48x^2-24x+84=

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3 0
3 years ago
A rock thrown vertically upward from the surface of the moon at a velocity of 36​m/sec reaches a height of s = 36t - 0.8 t^2 met
Verdich [7]

Answer:

a. The rock's velocity is v(t)=36-1.6t \:{(m/s)}  and the acceleration is a(t)=-1.6  \:{(m/s^2)}

b. It takes 22.5 seconds to reach the highest point.

c. The rock goes up to 405 m.

d. It reach half its maximum height when time is 6.59 s or 38.41 s.

e. The rock is aloft for 45 seconds.

Step-by-step explanation:

  • Velocity is defined as the rate of change of position or the rate of displacement. v(t)=\frac{ds}{dt}
  • Acceleration is defined as the rate of change of velocity. a(t)=\frac{dv}{dt}

a.

The rock's velocity is the derivative of the height function s(t) = 36t - 0.8 t^2

v(t)=\frac{d}{dt}(36t - 0.8 t^2) \\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(36t\right)-\frac{d}{dt}\left(0.8t^2\right)\\\\v(t)=36-1.6t

The rock's acceleration is the derivative of the velocity function v(t)=36-1.6t

a(t)=\frac{d}{dt}(36-1.6t)\\\\a(t)=-1.6

b. The rock will reach its highest point when the velocity becomes zero.

v(t)=36-1.6t=0\\36\cdot \:10-1.6t\cdot \:10=0\cdot \:10\\360-16t=0\\360-16t-360=0-360\\-16t=-360\\t=\frac{45}{2}=22.5

It takes 22.5 seconds to reach the highest point.

c. The rock reach its highest point when t = 22.5 s

Thus

s(22.5) = 36(22.5) - 0.8 (22.5)^2\\s(22.5) =405

So the rock goes up to 405 m.

d. The maximum height is 405 m. So the half of its maximum height = \frac{405}{2} =202.5 \:m

To find the time it reach half its maximum height, we need to solve

36t - 0.8 t^2=202.5\\36t\cdot \:10-0.8t^2\cdot \:10=202.5\cdot \:10\\360t-8t^2=2025\\360t-8t^2-2025=2025-2025\\-8t^2+360t-2025=0

For a quadratic equation of the form ax^2+bx+c=0 the solutions are

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=-8,\:b=360,\:c=-2025:\\\\t=\frac{-360+\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2-\sqrt{2}\right)}{4}\approx 6.59\\\\t=\frac{-360-\sqrt{360^2-4\left(-8\right)\left(-2025\right)}}{2\left(-8\right)}=\frac{45\left(2+\sqrt{2}\right)}{4}\approx 38.41

It reach half its maximum height when time is 6.59 s or 38.41 s.

e. It is aloft until s(t) = 0 again

36t - 0.8 t^2=0\\\\\mathrm{Factor\:}36t-0.8t^2\rightarrow -t\left(0.8t-36\right)\\\\\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}\\\\t=0,\:t=45

The rock is aloft for 45 seconds.

5 0
4 years ago
What is the value of x?
garri49 [273]

Answer:

x = 8

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

Sum the exterior angles and equate to 360

62 + 66 + 77 + 59 + 12x = 360, that is

264 + 12x = 360 ( subtract 264 from both sides )

12x = 96 ( divide both sides by 12 )

x = 8

7 0
3 years ago
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