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Alja [10]
3 years ago
5

The rectangle below has an area of x^2-x-72x 2 ?x?72 square meters and a length of x+8x+8 meters. What expression represents the

width of the rectangle?
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

Area of the rectangle is given by:

A = l \times w

where

A is the area of the rectangle

l is the length of the rectangle

w is the width of the rectangle respectively.

As per the given statement:

Area of the rectangle(A) =  x^2-x-72 square meters

length of the rectangle(l) = x+8

Substitute these in the given formula we have;

x^2-x-72 = (x+8) \times w

x^2-9x+8x-72 = (x+8) \times w

x(x-9)+8(x-9)= (x+8) \times w

or

(x+8)(x-9)= (x+8) \times w

Divide both sides by x+8 we have;

w = (x-9) meters.

Therefore, the expression represents the width of the rectangle is x-9 meters


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Vectorially speaking, the dilation is defined by following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

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First, we proceed to determine the coordinates of the dilated segment:

(P(x,y) = (10, 40), Q(x,y) = (70, 120), O(x,y) = (0,0), k = 5)

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)]

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Then, the length of the resulting segment is determined by following Pythagorean identity:

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l_{P'Q'} = 500

The length of the resulting segment is 500.

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