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Firlakuza [10]
3 years ago
10

The following data shows the low temperature in Vancouver, in degrees Celsius, for two weeks in January one year. 8.90, 8.35, 8.

40, 8.40, 8.50, 8.20, 8.50, 8.32, 8.50, 8.50, 8.60, 8.30, 8.10, 8.65 Which box plot best represents this data?

Mathematics
1 answer:
frutty [35]3 years ago
5 0
There is no option of the box plots, so I have created a version that would represent this data.

To make the box plot you will need the lower extreme, lower quartile, median, upper quartile, and upper extreme.

Please see the attached picture.

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Using the line of best fit, if your company wants to only pay $5.05 for each box of paper, how many boxes of paper should be ord
Yakvenalex [24]
Why do the paper towels cost so much? They super over pricing
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3 years ago
Ralph is an electrician. He charges an initial fee of $26, plus $31 per hour. If Ralph earned $119 on a job, how long did the jo
lubasha [3.4K]


3 hours

You can turn this into an equation:

F = 26 + 31t
Where F is the money Ralph earned, and t is the number of hours he worked.

Plugging in the 119 for F, we get
119 = 26 + 31t

93 = 31t

3 = t

5 0
3 years ago
Ajay bought a fan and a heater for rs 4000. He sold the fan at a profit of a 25% and the heater at a loss of 5%. If he gained 7%
Alborosie

Answer: Heater -Rs 2400; Fan- Rs 1600

Step-by-step explanation:

Given

Ajay bought a fan and a heater for Rs 4000

Suppose the price of fan is x and that of heater is 4000-x

Profit on the fan is 0.25x

Loss on heater is 0.05\times (4000-x)

Total profit is 7% i.e. 0.07\times 4000

\therefore 0.07\times 4000=0.25x-0.05(4000-x)\\\Rightarrow 280=0.25x-200+0.05x\\\Rightarrow 480=0.3x\\\Rightarrow x=1600

Thus, the price of heater is 4000-1600=Rs.\ 2400

Price of fan is Rs.\ 1600

Price of heater is Rs.\ 2400

8 0
3 years ago
The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each
Fynjy0 [20]

Answer:

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Step-by-step explanation:

Given equation of ellipsoids,

u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}

The vector normal to the given equation of ellipsoid will be given by

\vec{n}\ =\textrm{gradient of u}

            =\bigtriangledown u

           

=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})

           

=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}

           

=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}

Hence, the unit normal vector can be given by,

\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}

             =\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}

             

=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

Hence, the unit vector normal to each point of the given ellipsoid surface is

\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}

3 0
3 years ago
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