Using the quadratic formula to solve x2 = 5 – x, what are the values of x?
1 answer:
Answer:
x²=5-x
x²+x-5=0
1x²+1x²-5=0
[ax²+bx²+c=0]
∆=b²-4ac
∆=1²-4(-5)(1)=1+20=21
x=(-b±√∆)/2a
x=(-1±√21)/2
meaning:
x=(-1+√21)/2 or x=(-1-√21)/2
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