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bazaltina [42]
1 year ago
15

If f(n)= n²-n, then f(-4) is O-20 12 -12 20

Mathematics
1 answer:
Harman [31]1 year ago
3 0

Answer:

20

Step-by-step explanation:

Plug in -4 for n:

(-4)^2 - (-4) = 16 + 4 = 20

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Find two numbers with a sum of 20 and a difference of 14.
Alekssandra [29.7K]
The anwser is 17 and 3. 17+3=20, and the difference is 14!
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2 years ago
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Use a inequality symbol to compare -3x+7 -10-2
abruzzese [7]
Hey there,

Let's remember that a (inequality symbol) is things like (<), (>), (≤),(≥), (≠).

So, I believe that (-3x+7) and (-10-2) are separate. So we will find that out :)

Let's first do (-3x+7). As simplifying this expression here, we take that "x" of for a while and just stick to (-3+7). 

    -3
+   7
______
     4

Let's bring that "x" back, and the answer would be 4x for a while.

So far, 4x is the answer.
_____________________________________________________________

Now, Let's work on the other side.

We are talking about (<span>-10-2)

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-      2
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</span>     -12

So, by solving the answer to (-10-2), we got -12.

So, let's determine what is greater . . . . . 

What \ is \ greater?

-12 or 4.

-12 is on the negative side, and the number 4 is positive. This would conclude that 4 is great than -12.

Your correct answer would look like . . . 

<span>(-3x+7) > (-10-2)
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I really hope this helps you alot.

~Jurgen

8 0
2 years ago
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This is due today, and I have no idea what I'm doing, please help if you know anything.
defon

Binomial distribution formula: P(x) = (n  k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = \sqrt{np(1-p)}

stdev = \sqrt{(25)(0.04)(1-0.04)} = 0.9798

Hope this helps!! :)

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100%<br> &amp;<br> There are 16 girls and 18 boys in a class. The teacher chooses a student's name at<br> What is the probabilit
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Answer:a

Step-by-step explanation:

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Ainat [17]
I'm assuming, from what you've given me that the question is asking to do this.

15n=647
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