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2 years ago

If f(n)= n²-n, then f(-4) is O-20 12 -12 20

Mathematics

1 answer:

Harman [31]2 years ago

3 0

Answer:

Step-by-step explanation:

Plug in -4 for n:

(-4)^2 - (-4) = 16 + 4 = 20

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If f(x)=3x^2 +1 and g(x)=1-x, what is the value of (f-g)(2)

liraira [26]

$(f-g)(x)=3x^2+1-(1-x)=3x^2+1-1+x=3x^2+x\\\\ (f-g)(2)=3\cdot2^2+2=14$

5 0

3 years ago

The sum of two consecutive integers is 7,903. What are the integers.

dimaraw [331]

The answer for the first question would be 3952+3952 =7903

5 0

4 years ago

Read 2 more answers

a farmer is planning a rectangular area for her chickens. the area of the rectangle will be 200 square feet. three sides of the

Vladimir79 [104]

Let

x---------> the length side of the rectangular area

y---------> the width side of the rectangular area

we know that

the area of the rectangle is equal to

$A=x*y\\ A= 200\ ft^{2} \\ x*y=200$

$y=\frac{200}{x}$ -----> equation $1$

The perimeter of the rectangle is equal to

$P=2x+2y$

but remember that the fourth side of the rectangle will be formed by a portion of the barn wall

$P=x+2y$ -----> equation $2$

To minimize the cost we must minimize the perimeter

Substitute the equation $1$ in the equation $2$

$P=x+2*[\frac{200}{x} ]$

Using a graph tool

see the attached figure

The minimum of the graph is the point $(20,40)$

that means for $x=20\ ft$

the perimeter is a minimum and equal to $40\ ft$

Find the value of y

$y=\frac{200}{x}$

$y=\frac{200}{20}$

$y=10\ ft$

The cost of fencing is equal to

$5*40= \$200$

therefore

the answer is

the length side of the the fourth wall will be $20\ ft$

7 0

3 years ago

How many groups of 1/4 are in 3. Draw a tape diagram

BaLLatris [955]

Answer:

12 groups of 1/4

Step-by-step explanation:

Look up the tape diagram part

8 0

3 years ago

Question 1: The diagonal of a rectangle, with base x, remains at a fixed

kramer

We have that The height changing rate when the length of the base is 2 cm

$dh/dt=-7.2cm/s$

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle is mathematically given

$r^2=h^2+x^2$

With r=3

Therefore

dx/dt=8cm/s

Hence

$2rdr/dt=2hdh/dt+2xdx/dt\\\\\dh/dt=\frac{-x}{r^2-x^2}dx/dt$

We have

$dh/dt=-2/\sqrt{5}(8)\\\\dh/dt=-7.2cm/s$

Therefore

The height changing rate when the length of the base is 2 cm

$dh/dt=-7.2cm/s$

For more information on this visit

brainly.com/question/23366835

4 0

3 years ago